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horrorfan [7]
3 years ago
15

The lithosphere, hydrosphere, and ______________ are the abiotic parts of the planet.

Chemistry
1 answer:
VladimirAG [237]3 years ago
8 0
The lithosphere, hydrosphere, and atmosphere are the abiotic parts of the planet.
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Gas law problem: A gas has a volume of 800 mL at -25℃ and 600 kPa. What would the volume of the gas be at 227℃ and 1000 kPa?
Sati [7]
<h3><u>Answer;</u></h3>

= 930.23 mL

<h3><u>Explanation</u>;</h3>

Using the combined gas law;

P1V1/T1 = P2V2/T2

Where; P1 = 600 kPa, V1 = 800 mL, and T1 = -25 +273 = 258 K, and

V2= ?, P2 = 1000 kPa, and T2 = 227 +273 = 500 K

Thus;

V2 = P1V1T2/T1P2

     = (600 ×800 ×500) / (258 × 1000)

     = 930.23 mL

5 0
3 years ago
Please help! ill give you 90 points!
Luba_88 [7]

Answer:

1.d = 2.70 g/mL

2.d = 13.6 g/mL

4.d = 1896 g / 212.52 cm3 = 8.9 g/cm3

Explanation:If this helped subscribe to Amiredagoat Yt

3 0
3 years ago
Identify the atom that increases in oxidation number in this redox reaction: 2MnO2 + 2K2CO3 + O2 → 2KMnO4 + 2CO2
Aneli [31]
2Mn⁺⁴O2 + 2K2CO3 + O2 → 2KMn⁺⁷O4 + 2CO2

Mn⁺⁴ - 3e⁻ = Mn⁺⁷
5 0
3 years ago
The atomic radius of a gold atom is 144×10^-12. The volume of a gold atom can be calculated using the volume of a sphere. The de
Alekssandra [29.7K]
Given:
Atomic radius of gold = 144 x 10⁻¹² m = 144 pm 
Density of gold = 19.3 g/cm³ = 19.3 x 10⁻³ kg/cm³
Mass of gold sample = 1.40 g = 1.4 x 10⁻³ kg

Calculate the volume of an atom. 
v = [(4π)/3]*(144 x 10⁻¹² m)³ = 1.2508 x 10⁻²⁹ m³

Calculate the mass of an atom.
m=(1.2508\tmes10^{-29}\,m^{3})*(19.3\times 10^{-3}\, \frac{kg}{cm^{3}} )*(10^{2}\, \frac{cm}{m})^{3} \\ = 2.4142 \times 10^{-25}  \, kg

Calculate the number of atoms in a sample of mass 1.40 g.
N =  \frac{1.40 \time 10^{-3} kg}{2.4142 \times 10^{-25} \,  \frac{kg}{atom} } =5.8 \times 10^{21} \, atoms

Answer:  5.8 x 10²¹ atoms
3 0
3 years ago
I need help for my HW Assignment
marysya [2.9K]
- 402 has 3 sig figs.
- 0.00560 has 3 sig figs.
- 34.20 has 3 sig figs.
- 6546 has 4 sig figs.
- 45000 has 2 sig figs.

hope this helps :)
7 0
3 years ago
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