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Bas_tet [7]
3 years ago
7

Clothes in a dryer acquire static cling by

Physics
2 answers:
Gnoma [55]3 years ago
5 0
<span>The answer is friction. The force acting upon the comparative motion of solid surfaces, liquid layers, and material elements sliding in contradiction of each other. When sides in contact move comparative to each other, the friction amid the two surfaces changes kinetic energy into thermal energy; in other words work to heat. </span>
Artyom0805 [142]3 years ago
5 0

The answer is friction. The force acting upon the comparative motion of solid surfaces, liquid layers, and material elements sliding in contradiction of each other. When sides in contact move comparative to each other, the friction amid the two surfaces changes kinetic energy into thermal energy; in other words work to heat.

Explanation:

Friction. You will discern that natural fibers, wool, and cotton do not have static. All performed fibers comprise elements that when scraped together will have static electricity.would have believed that the stainless-steel drum and another metalwork of the dryer would remove the static charge to earth. Unless of course your machine is not earthed .

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A cylinder 8 in in diameter and 3 ft long is concentric with a pipe of 8.25 in internal diameter. Between the cylinder and the p
Aleks [24]

Answer:

623.5lb

Explanation:

The answer is detailed in the attached photo

7 0
3 years ago
What is the molar mass of a gas if 1.30g of the gas has a volume of 245mL at STP? ...?
padilas [110]
First, we assume this as an ideal gas so we use the equation PV=nRT. Then, we use the conditions at STP that would be 1 atm and 273.15 K. We calculate as follows:

PV= nRT
PV= mRT/MM

1 atm (.245 L) =1.30(0.08206)(273.15) / MM
MM = 118.94 g/mol <--- ANSWER
5 0
3 years ago
Michelle wants to Salt from water. She tried pouring the salt water through a piece of filter paper, but the salt did not separa
Katarina [22]
C. Let the water evaporate
3 0
3 years ago
Five men push a stalled car with an average force of 400 N per person. Find the mass of the
timama [110]

The mass of the car is 2000 kg

Explanation:

We can solve this problem by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

In this problem, we have:

a=1 m/s^2 is the acceleration of the car

Each person applies a force of 400 N, and there are five men, so the total force applied is

\sum F = 5\cdot 400 N = 2000 N

Therefore, the mass of the car is:

m=\frac{\sum F}{a}=\frac{2000 N}{1 m/s^2}=2000 kg

Learn more about Newton's second law of motion:

brainly.com/question/3820012

#LearnwithBrainly

4 0
4 years ago
A force F = (2.75 N)i + (7.50 N)j + (6.75 N)k acts on a 2.00 kg mobile object that moves from an initial position of d = (2.75 m
Natasha2012 [34]

Answer:

The work done on the object by the force in the 5.60 s interval is 40.93 J.

Explanation:

Given that,

Force F=(2.75\ N)i+(7.50\ N)j+(6.75\ N)k

Mass of object = 2.00 kg

Initial position d=(2.75)i-(2.00)j+(5.00)k

Final position d=-(5.00)i+(4.50)j+(7.00)k

Time = 4.00 sec

We need to calculate the work done on the object by the force in the 5.60 s interval.

Using formula of work done

W=F\cdot d

W=F\cdot(d_{f}-d_{i})

Put the value into the formula

W=(2.75)i+(7.50)j+(6.75)k\cdot (-(5.00)i+(4.50)j+(7.00)k-(2.75)i+(2.00)j-(5.00)k)

W=(2.75)i+(7.50)j+(6.75)k\cdot((-7.75)i+6.50j+2.00k)

W=2.75\times-7.75+7.50\times6.50+6.75\times2.00

W=40.93\ J

Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.

4 0
3 years ago
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