Answer:
623.5lb
Explanation:
The answer is detailed in the attached photo
First, we assume this as an ideal gas so we use the equation PV=nRT. Then, we use the conditions at STP that would be 1 atm and 273.15 K. We calculate as follows:
PV= nRT
PV= mRT/MM
1 atm (.245 L) =1.30(0.08206)(273.15) / MM
MM = 118.94 g/mol <--- ANSWER
The mass of the car is 2000 kg
Explanation:
We can solve this problem by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

where
is the net force
m is the mass
a is the acceleration
In this problem, we have:
is the acceleration of the car
Each person applies a force of 400 N, and there are five men, so the total force applied is

Therefore, the mass of the car is:

Learn more about Newton's second law of motion:
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Answer:
The work done on the object by the force in the 5.60 s interval is 40.93 J.
Explanation:
Given that,
Force 
Mass of object = 2.00 kg
Initial position 
Final position 
Time = 4.00 sec
We need to calculate the work done on the object by the force in the 5.60 s interval.
Using formula of work done


Put the value into the formula




Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.