Answer:
Average net force, F = 15157.15 N
Explanation:
It is given that,
The mass of the car and riders is, 
Initial speed of the car, u = 0
Final speed of the car, v = 43.4 m/s
Time, t = 8.59 seconds
We need to find the average net force exerted on the car and riders by the magnets. It can be calculated using second law of motion as :
F = m a


F = 15157.15 N
So, the average net force exerted on the car and riders by the magnets. Hence, this is the required solution.
Answer:
Value of magnitude of acceleration will be 
Explanation:
It is given that when a stone is dropped it takes 2.2 sec to reach the ground
(a) As the stone is dropped from the top of building
So its initial velocity
will be 0 m /sec
(b) As the stone is free falling and there is no external force applied on it so its acceleration will be equal to acceleration due to gravity
So value of magnitude of acceleration will be equal to
Midway between the two<span> solstices we have equinoxes – Vernal Equinox in March and </span>Autumnal Equinox<span> in September. ... After this time, the Earth's northern axis is tilted </span>more<span> and </span>more<span>towards ... Then on </span>Summer Solstice<span>, the Sun will reach its farthest north position in the sky</span>
Answer:
Explanation:
a) I = ½mR² = ½(19)(0.15²) = 0.21375 kg•m²
b) τ = Fnet(r) = (25 - 12)(0.15) = 1.95 N•m
c) CCW
d) a = τ/I = 1.95 / 0.21375 = 9.12280701... = 9.1 rad/s²
e) CCW