Answer:
Explanation:
Given:
the displacement as the function of time:
here time is in seconds and the displacement in meters.
Now we differentiate this eq. of displacement to get the equation of velocity:
According to given the velocity is 
at some time:
& is the only time for (t>=0) instances when the particle will have a velocity of but in the opposite direction.
Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4 
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) = 
⇒ P = 
⇒ P = 16 
This is the pressure inside the cylinder.
Let force applied on the brake pad = 
Area of the brake pad (
)= 1.7
Thus the pressure on the brake pad (
) = 
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P =
⇒ 16 =
⇒ = 16 ×
Put the value of we get
⇒ = 16 × 1.7
⇒ = 27.2 lb
This the total force applied during braking.
The force applied on one wheel = 
= 
= 6.8 lb
⇒ The force applied on one wheel during braking.
Wavelength = 600 nm = 600 × 10^(-9)
speed of light = c = 3 × 10^8
planck constant = h = 6.63 × 10^(-34)
energy of photon = hc/wavelength
= 6.63 × 10^(-34) × 3 × 10^8/600 × 10^(-9)
= 1.9 × 10^(-25)/6 × 10^(-7)
= 0.31 × 10^(-16)
= 3.1 × 10^(-17)
Based on the Newton's second law of motion, the value of the net force acting on the object is equal to the product of the mass and the acceleration due to gravity. If we let a be the acceleration due to gravity, the equation that would allow us to calculate it's value is,
W = m x a
where W is weight, m is mass, and a is acceleration. Substituting the known values,
40 kg m/s² = (10 kg) x a
Calculating for the value of a from the equation will give us an answer equal to 4.
ANSWER: 4 m/s².
