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Eduardwww [97]
3 years ago
12

The largest building in the world by volume is the Boeing 747 plant in Everett, Washington. It measures approximately 634 m long

, 710 yards wide, and 109 ft high. volume in feet^3
Physics
2 answers:
Mazyrski [523]3 years ago
8 0
So to get the volume, you're going to multiply all three together, but you have to make all the units the same first. The answer wants ft³, so you want to convert them all to feet. height = 109 ft, so that's fine already. Awesome. width = 710 yd, but that's an easy conversion to feet. Three feet equal one yard, so just multiply (710 yd) by (3 ft/1 yd) and that'll give you the width in ft. length = 634 m This one is a little tricker, but same principle. First convert meters to centimeters, like this: (634 m)(100 cm/1 m). Then take that number in cm and convert it into inches, knowing that 1 inch = 2.54 centimeters. So multiply the inches you have by (1 in/2.54 cm). Then you'll change that number into feet by dividing it by twelve, since there are twelve inches in each foot. Now you have all three measurements in feet. Just multiply them together to get the volume in ft³ and you're good to go! :)
Mice21 [21]3 years ago
4 0
The volume  =  (length) x (width) x (height) .

But before we can do the multiplication, all three dimensions
have to be in the same unit.

The question is asking for the answer in cubic feet, and one of
the dimensions is already in feet.  So let's change the other two
dimensions to feet.

Length:
1 meter = 3.28 feet
634 meters = (634 x 3.28) feet

Width:
1 yard = 3 feet
710 yards = (710 x 3) feet

Height:
109 feet

Volume  =     (length)          x        (width)       x   (height)

               = (634 x 3.28 ft)    x    (710 x 3 ft)    x    (109 ft)

               =        48,292,580 cubic feet .
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A long wire carries a current toward the north in a magnetic field that is directed vertically downward perpendicular to the sur
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Professional Application: A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 11
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Answer:

0.182 m/s

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Suppose that a solid ball, a solid disk, and a hoop all have the same mass and the same radius. Each object is set rolling witho
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Answer:

Hoop will reach the maximum height

Explanation:

let the mass and radius of solid ball, solid disk and hoop be m and r  (all have same radius and mass)

They all  are rolled with similar initial speed v

by the law of conservation of energy we can write

K_{trans}+K_{rot}= P

for solid ball

[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{ball}\omega^2= mgh_{ball}

putting I_{ball}=\frac{2}{5}mr^2 and \omega=\frac{v}{r} in the above equation and solving we get

h_{ball}= 0.071v^2

now for solid disk

[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{disk}\omega^2= mgh_{disk}

putting I_{ball}=\frac{1}{2}mr^2 and \omega=\frac{v}{r} in the above equation and solving we get

h_{disk}= 0.076v^2

for hoop

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putting I_{hoop}=mr^2 and \omega=\frac{v}{r} in the above equation and solving we get

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