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drek231 [11]
4 years ago
9

The luminous star Alnilam in the Orion belt is 1,340 light-years away from Earth. Use the conversion factor 1 parsec = 3.262 lig

ht-years to find the closest conversion of this distance from light-years to parsecs (pc).

Physics
2 answers:
svlad2 [7]4 years ago
8 0

The answer is 410.8 pc.

Angelina_Jolie [31]4 years ago
6 0

Answer:

The distance to the star Alnilam in the Orion belt is 410.8 Pc

Explanation:

The angle due to the change in position of a nearby object against the background stars is known as parallax. This angle is gotten when the position of the object is measured in January and then in July according to the configuration of the Earth with respect to the Sun in those months (see the image below).

       

The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth(as is shown in the image below), knowing that the distance between the Earth and the Sun (150000000 Km) is defined as 1 astronomical unit:

\tan{p} = \frac{1AU}{d}

Where d is the distance to the star.

p('') = \frac{1}{d}    (1)  

Equation (1) can be rewritten in terms of d:

d(pc) = \frac{1}{p('')}  (2)

Equation (2) represents the distance in a unit known as parsec (pc), which is the distance of a star with a parallax angle of 1 arc second.

For the case of the star Alnilam in the Orion belt ( 1340 light-years):

Since 1 parsec is equivalent to 3.262 light-years, therefore:

d = 1340 ly \cdot \frac{1pc}{3.262 ly} ⇒ $410.8 Pc

Notice how both , Light years and parsecs are units for distance.          

Key terms:

Parsec: Parallax of arc second.

Light-year: Distance traveled by light in one year.

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3 years ago
There are two unitless vectors:
Hunter-Best [27]

Answer:

200.38^0

Explanation:

Given the forces:

F1 = 8.92 i + 17.37 j

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If a third vector is added to them such that they add up to to the null vector as F1 + F2 + F3 = 0

then to get F3:

F3 = -F2-F1

F3 = -(8.31 i - 10.97 j)-(8.92 i + 17.37 j )

F3 = -8.31 i + 10.97 j-8.92 i - 17.37 j

F3 = -8.31i-8.92i+10.97j-17.37j

F3 = -17.23i-6.4j

from the vector:

x = -17.23 and y = -6.4

angle of the third vector with respect to the +x-axis is expressed as:

\theta = tan^{-1}\frac{y}{x}\\ \theta = tan^{-1}\frac{-6.4}{-17.23}\\\theta = tan^{-1}0.3715\\\theta = 20.38^0

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4 0
4 years ago
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5 0
2 years ago
The stone, which weighs 400 g, is thrown upwards at a speed of 20 m / s. Climbed to a height of 12 m. Determine: what is equal t
maxonik [38]

Given that,

Mass of the stone, m = 400 g = 0.4 kg

Initial speed, u = 20 m/s

It is climbed to a height of 12 m.

To find,

The work done by the resistance force.

Solution,

Let v is the final speed. It can be calculated by using the conservation of energy.

v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 12} \\\\v=15.33\ m/s

Work done is equal to the change in kinetic energy. It can be given as follows :

W=\dfrac{1}{2}m(v^2-u^2)\\\\=\dfrac{1}{2}\times 0.4\times (15.33^2-20^2)\\\\=-32.99\ J

So, the required work done is 32.99 J.

3 0
3 years ago
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