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Kazeer [188]
3 years ago
10

Plz help me!!!!!!!!!!!!!!

Chemistry
1 answer:
tester [92]3 years ago
3 0
It's a because it's a
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What is the third most common gas found in the air we breathe?
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Argon is the third most common gas found in the air we breathe. The air we breathe has approximately 78% nitrogen and 21 % oxygen. The third more abundant gas in the air we breathe is Argon. It is available in a very small quantity in the air that we breathe. The percentage of the gas argon is about 0.9% in the air that we breathe. There are several other gases also present in the air that we breathe, but they are found mostly in negligible amounts.



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3 years ago
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How many moles are in 8.90 X 10^24 atoms of Na?
mixas84 [53]

Answer:

1.48 x 10^47 mol of Na

Explanation:

8.90 x 10^24 atoms of Na (1 mol of Na/6.022 x 10^23 atoms of Na)=

1.48 x 10^47 mol of Na

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3 years ago
Consider the following intermediate chemical equations.
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Which factors can influence the length of time it takes for a half-life to occur?
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Answer:

the radioactive half-life of an atom can depend on how it is bonded to other atoms. by changing the neighboring atoms that are bonded to a radioactive isotope, we can change its half-life.

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4 0
3 years ago
At 500 degree C, F_2 gas is stable and does not dissociate, but at 840 degree C, some dissociation occurs: F_2 (g) 2 F(g). A fla
bazaltina [42]

Answer:

2.73 is the equilibrium constant for the dissociation of F_2 gas at 840 degree Celsius.

Explanation:

F_2(g)\rightleftharpoons 2F(g)

Initial

0.600 atm    0

Equilibrium

(0.600 atm - p)        2p

Total pressure at equilibrium = P = 0.984 atm

P= 0.600 atm - p)+2p=0.984 atm

p = 0.384 atm

Partial pressure of the F_2 gas , p_{f_2}= (0.600 atm - 0.384 atm)=0.216 atm

Partial pressure of the F gas, p_{f} = 2(0.384 atm)=0.768 atm

K_p=\frac{(p_{F})^2}{p_{F_2}}

K_p=\frac{(0.768 atm)^2}{0.216 atm}=2.73

2.73 is the equilibrium constant for the dissociation of F_2 gas at 840 degree Celsius.

7 0
4 years ago
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