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Diano4ka-milaya [45]
3 years ago
8

Two identical charges are separated by a distance d. If the distance between them is increased to 3d, what will happen to the fo

rce of repulsion between them? A) It will be one-ninth the original force. B) It will be one-third the original force. C) It will be nine times the original force. D) It will be three times the original force.
Physics
2 answers:
nirvana33 [79]3 years ago
5 0

Answer:

A

Explanation:

belka [17]3 years ago
3 0
A-It will be one-ninth the original force
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The correct answer is: 
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Sergeeva-Olga [200]

Answer:

(a) 32.5 kgm/s

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Then, the change in momentum of the body is of 32.5 kgm/s (a).

Now, from the impulse-momentum theorem, we know that the change in momentum of a body \Delta p is equal to the impulse I exerted to it. So, the impulse produced by the force equals 32.5 kgm/s (or 32.5 Ns) (b).

Finally, since we know the value of the impulse and the interval of time, we can easily solve for the magnitude of the force:

I=F\Delta t\\\\\implies F=\frac{I}{\Delta t}\\\\F=\frac{32.5Ns}{3.0s}\\\\F=10.8N

It means that the magnitude of the force is of 10.8N (c).

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