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3 years ago

Which dog has the most kinetic energy?

Physics

2 answers:

Nadya [2.5K]3 years ago

5 0

A. A dog of mass 14kg running with the speed of 3m/s

Furkat [3]3 years ago

3 0

Nobody actually needs to know how much kinetic energy any of these dogs has.

The purpose of this question is to help you discover whether you know how to calculate kinetic energy, and then to give you some practice at doing it.

You have to calculate the kinetic energy of each dog, and then review your results to see which dog has the most.

The whole secret behind working this problem is the formula for the kinetic energy of any object:

Kinetic Energy = (1/2) · (mass) · (speed)²

The little ² next to 'speed' means 'squared' or 'multiplied by itself'.

(speed)² means (speed · speed) .

So, in order to calculate how much kinetic energy an object has, here's what you do:

-- Take the object's speed. Multiply the speed by itself.

-- Take that number and multiply it by the object's mass.

-- Take that number and throw away half of it.

So now here we go:

Dog A: KE = (1/2) (14 kg) (2 m/s)² = 28 Joules

Dog B: KE = (1/2) (14 kg) (3 m/s)² = 63 Joules

Dog C: KE = (1/2) (11 kg) (5 m/s)² = 137.5 Joules

Dog D: KE = (1/2) 12 kg) (4 m/s)² = 96 Joules

==> Dog C has more kinetic energy than any of the other 3 dogs.

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Is a perch a consumer or...

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Yes a perch is a consumer.

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4 years ago

The force exerted by the wind on the sails of a sailboat is Fsail = 330 N north. The water exerts a force of Fkeel = 210 N east.

Elena L [17]

Answer:

The magnitude of the acceleration is $a_r = 1.50 \ m/s^2$

The direction is $\theta = 32.5 6^o$ north of east

Explanation:

From the question we are told that

The force exerted by the wind is $F_{sail} = (330 ) \ N \ north$

The force exerted by water is $F_{keel} = (210 ) \ N \ east$

The mass of the boat(+ crew) is $m_b = 260 \ kg$

Now Force is mathematically represented as

$F = ma$

Now the acceleration towards the north is mathematically represented as

$a_n = \frac{F_{sail}}{m_b}$

substituting values

$a_n = \frac{330 }{260}$

$a_n = 1.269 \ m/s^2$

Now the acceleration towards the east is mathematically represented as

$a_e = \frac{F_{keel}}{m_b }$

substituting values

$a_e = \frac{210}{260}$

$a_e =0.808 \ m/s^2$

The resultant acceleration is

$a_r = \sqrt{a_e^2 + a_n^2}$

substituting values

$a_r = \sqrt{(0.808)^2 + (1.269)^2}$

$a_r = 1.50 \ m/s^2$

The direction with reference from the north is evaluated as

Apply SOHCAHTOA

$tan \theta = \frac{a_e}{a_n}$

$\theta = tan ^{-1} [\frac{a_e}{a_n } ]$

substituting values

$\theta = tan ^{-1} [\frac{0.808}{1.269 } ]$

$\theta = tan ^{-1} [0.636 ]$

$\theta = 32.5 6^o$

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4 years ago

Coherent green light shines on a double slit with spacing 241um. This results in a diffraction pattern consisting of a central m

lilavasa [31]

Answer:

Becomes greater

Explanation:

Distance between the central maxima and the next line increase with the wavelength i.e.

$d =\frac{3 \lambda L}{2a}$

As, the wavelength of the red light is greater than the wavelength of the green light, thus, the distance between the central maxima and the next line becomes greater.

Option 5 is correct.

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4 years ago

A metal and a non-metal typically form covalent compounds. True False

alexandr1967 [171]

Answer:

That is true. They share atoms with each other. I hope this helps. Comment if you have any question

Explanation:

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4 years ago

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Answer:

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3 years ago