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3 years ago

A mature thunderstorm will contain both updrafts and downdrafts. True or False

Physics

2 answers:

jasenka [17]3 years ago

7 0

A mature thunderstorm will contain both updraft and downdrafts. The given statement is true.

When the cumulus cloud becomes very large, the water in it becomes large and heavy. Raindrops start to fall through the cloud when the rising air can no longer hold them up. Meanwhile, cool dry air starts to enter the cloud. Because cool air is heavier than warm air, it starts to descend in the cloud (known as a downdraft). The downdraft pulls the heavy water downward, making rain.

This cloud has become a cumulonimbus cloud because it has an updraft, a downdraft, and rain. Thunder and lightning start to occur, as well as heavy rain. The cumulonimbus is now a thunderstorm cell.

Paul [167]3 years ago

3 0

Answer:

A mature thunderstorm will contain both updraft and downdrafts. The given statement is true.

Explanation:

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Need help asap please and thank you

nordsb [41]

Distance = speed x time

distance = 116 x 10

distance = 1160 m

6 0

3 years ago

When a object is at rest, what is it’s speed??

nadya68 [22]

Answer:

0 (there is no speed)

Explanation:

If an object is at rest, it is not moving, and it doesn't have a speed, so the speed is zero.

3 0

3 years ago

Read 2 more answers

A small object with momentum 7.0 kg∙m/s approaches head-on a large object at rest. The small object bounces straight back with a

EastWind [94]

Answer:

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

Explanation:

Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:

$p_{S,1}+p_{B,1} = p_{S,2}+p_{B,2}$ (1)

Where:

$p_{S,1}$ , $p_{S,2}$ - Initial and final momemtums of the small object, measured in kilogram-meters per second.

$p_{B,1}$ , $p_{B,2}$ - Initial and final momentums of the big object, measured in kilogram-meters per second.

If we know that $p_{S,1} = 7\,\frac{kg\cdot m}{s}$ , $p_{B,1} = 0\,\frac{kg\cdot m}{s}$ and $p_{S, 2} = 4\,\frac{kg\cdot m}{s}$ , then the final momentum of the big object is:

$7\,\frac{kg\cdot m}{s} + 0\,\frac{kg\cdot m}{s} = 4\,\frac{kg\cdot m}{s}+p_{B,2}$

$p_{B,2} = 3\,\frac{kg\cdot m}{s}$

The magnitude of the large object's momentum change is:

$p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}-0\,\frac{kg\cdot m}{s}$

$p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}$

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

4 0

3 years ago

Can a cyclic group have more than one generator

AleksandrR [38]

A cyclic, or not, group can have lots of sets of generators with different cardinalities, a cyclic group is characterized for having a generator set with 1 single element. A generator for a cyclic group and any other element will also be a generator set.

3 0

3 years ago

Middle C, also known as do on the fixed do-solfge scale, is a note used when playing or singing music. The frequency of middle C

Ahat [919]

Answer:

The speed of sound for middle C is 345.01 m/s.

Explanation:

Given that,

The frequency of middle C is 261.63 Hz

The wavelength of middle C note used when playing or singing music, $\lambda=131.87\ cm=1.3187\ m$

We need to find the speed of sound for middle C. We know that the relation between speed, frequency and wavelength is given by the formula as follows :

$v=f\lambda\\\\v=261.63\ Hz\times 1.3187\ m\\\\v=345.01\ m/s$

So, the speed of sound for middle C is 345.01 m/s. Hence, this is the required solution.

8 0

3 years ago