A 4.00-kg cylinder, of length 21.0 cm and diameter 12.0 cm , about the central axis of the cylinder, if the cylinder is thin-wal
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Answer:
Maximum acceleration in the simple harmonic motion will be
Explanation:
We have given amplitude of simple harmonic motion is A = 0.43 m
Time period of the oscillation is T = 3.9 sec
We have to find the maximum acceleration
For this we have to find the angular frequency
Angular frequency will be equal to
Maximum acceleration is given by
So maximum acceleration in the simple harmonic motion will be