Answer: destructive interference
Explanation:
Natural gas is the answer.
Answer:
E. d and O
Explanation:
"Light passing through a single slit forms a diffraction pattern somewhat different from those formed by double slits or diffraction gratings".
According to Huygens’s principle, "for each element of the wavefront in the slit emits wavelets. These are like rays that start out in phase and head in all directions. (Each ray is perpendicular to the wavefront of a wavelet.) Assuming the screen is very far away compared with the size of the slit, rays heading toward a common destination are nearly parallel".
The destructive interference for a single slit is given by:
![d sin \theta = m\lambda , m=1,-1,2,-2,3,...](https://tex.z-dn.net/?f=d%20sin%20%5Ctheta%20%3D%20m%5Clambda%20%2C%20m%3D1%2C-1%2C2%2C-2%2C3%2C...)
Where
d is the slit width
is the light's wavelength
is the angle relative to the original direction of the light
m is the order od the minimum
I represent the intensity
When the intensity and the wavelength are incident normally the angular as we can see on the expression above the angular separation just depends of the distance d and the wavelength O.
Answer:
in accelerated motion
Explanation: tbh I just guessed if im wrong sorry
Let the ball is initially at point P1. Finally it reaches at point P2.( bottom most). Since only conservative force is acting on the ball throughout the motion, mechanical energy will be conserved. Therefore conserving energy from P1 to P2,
Initially ball is at rest(P1). So initial kinetic energy is 0. Let ball is at height h1 initially, so initial potential energy = mgh ( m= mass of the ball). At bottom most point (P2), potential energy of ball changes into kinetic energy. So final kinetic energy =1/2 mv^2. Final potential energy = 0. Equating energies at P1 and P2,
Mgh= 1/2 mv^2. Therefore, v= (2gh)^1/2. Since all the initial and final points are at same height, velocity will be same for all the paths(irrespective of the path taken by ball). So velocity will be same.