This would be true. On Jupiter you would weigh 234 pounds if you were 100 pounds on Earth.
Answer:
a. The moment of the 4 N force is 16 N·m clockwise
b. The moment of the 6 N force is 12 N·m anticlockwise
Explanation:
In the figure, we have;
The distance from the point 'O', to the 6 N force = 2 m
The position of the 6 N force relative to the point 'O' = To the left of 'O'
The distance from the point 'O', to the 4 N force = 4 m
The position of the 4 N force relative to the point 'O' = To the right of 'O'
a. The moment of a force about a point, M = The force, F × The perpendicular distance of the force from the point
a. The moment of the 4 N force = 4 N × 4 m = 16 N·m clockwise
b. The moment of the 6 N force = 6 N × 2 m = 12 N·m anticlockwise.
Wavelength = 20 m = 0.20 m
frequency = 3*10^8 / 0.20 = 1.5 * 10^9 Hertz
Answer:0.0704 kg
Explanation:
Given
initial Absolute pressure
=210+101.325=311.325
![T_1=25^{\circ}\approx 298 K](https://tex.z-dn.net/?f=T_1%3D25%5E%7B%5Ccirc%7D%5Capprox%20298%20K)
![V=0.025 m^3](https://tex.z-dn.net/?f=V%3D0.025%20m%5E3)
![T_2=50^{\circ}\approx 323 K](https://tex.z-dn.net/?f=T_2%3D50%5E%7B%5Ccirc%7D%5Capprox%20323%20K)
as the volume remains constant therefore
![\frac{P_1}{T_1}=\frac{P_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2%7D%7BT_2%7D)
![\frac{311.325}{298}=\frac{P_2}{323}](https://tex.z-dn.net/?f=%5Cfrac%7B311.325%7D%7B298%7D%3D%5Cfrac%7BP_2%7D%7B323%7D)
![P_2=337.44 KPa](https://tex.z-dn.net/?f=P_2%3D337.44%20KPa)
therefore Gauge pressure is 337.44-101.325=236.117 KPa
Initial mass ![m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}](https://tex.z-dn.net/?f=m_1%3D%5Cfrac%7BP_1V%7D%7BRT_1%7D%3D%5Cfrac%7B311.325%5Ctimes%200.025%7D%7B0.0287%5Ctimes%20298%7D)
![m_1=0.91 kg](https://tex.z-dn.net/?f=m_1%3D0.91%20kg)
Final mass ![m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}](https://tex.z-dn.net/?f=m_2%3D%5Cfrac%7BP_2V%7D%7BRT_2%7D%3D%5Cfrac%7B311.325%5Ctimes%200.025%7D%7B0.0287%5Ctimes%20323%7D)
![m_2=0.839](https://tex.z-dn.net/?f=m_2%3D0.839)
Therefore
=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back
Gravity accelerates you at 9.8 meters per second per second. After one second, you're falling 9.8 m/s. After two seconds, you're falling 19.6 m/s, and so on.