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Lynna [10]
4 years ago
13

An unknown element (called Z) is being researched in the lab. Scientists perform mass spectrophotometry on a sample of the eleme

nt Z and find the element has four isotopes (mass data below). Use the data in the table to determine the average atomic mass of the unknown element Z.
Isotope Atomic Mass Abundance
Z - 24 23.985 amu 78.90%
Z - 25 24.995 amu 10.00%
Z - 26 25.982 amu 11.00%
Z - 28 27.967 amu 0.10%

Fun question. Best answer 10 points. :) Show your work!
Chemistry
1 answer:
Minchanka [31]4 years ago
3 0

The average atomic mass is = ∑Mi X (Percentage)i / 100

Mi = atomic mass of isotope

Percentage = the percentage of that isotope

so for given

sotope Atomic Mass Abundance

Z - 24 23.985 amu 78.90%

Z - 25 24.995 amu 10.00%

Z - 26 25.982 amu 11.00%

Z - 28 27.967 amu 0.10%

The average atomic mass

= (23.985 X 78.90% + 24.995 X 10.00% + 25.982X 11.00%  + 27.967 X 0.10%) / 100

= 24.3097 amu

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Which statement best describes alpha decay?(1 point)
Veseljchak [2.6K]

Answer:

After the ejection of an alpha particle, the remaining nucleus has a mass number that is four less and an atomic number that is two less, so alpha decay is a type of nuclear fission.

6 0
3 years ago
Calculate the molarity of a solution that contains 4.7 moles in 5.2 liters.
AleksAgata [21]

Answer:

0.9M

Explanation:

molarity = mols/L

M=4.7mol/5.2L

= 0.9M

4 0
3 years ago
If the molecule could move upward without colliding with other molecules, then how high would it go before coming to rest? Give
tankabanditka [31]

The maximum height at which nitrogen molecule will go before coming to rest is 14 kilometers.

Given:

The nitrogen gas molecule with a temperature of 330 Kelvins is released from Earth's surface to travel upward.

To find:

The maximum height of a nitrogen molecule when released from the Earth's surface before coming to rest.

Solution:

  • The maximum height attained by nitrogen gas molecule = h
  • The temperature of nitrogen gas particle = T = 330 K

The average kinetic energy of the gas particles is given by:

K.E=\frac{3}{2}K_bT\\\\K.E=\frac{3}{2}\times 1.38\times 10^{-23} J/K\times 330 K\\\\K.E=6.381\times 10^{-21} J

The nitrogen molecule at its maximum height will have zero kinetic energy as all the kinetic energy will get converted into potential energy

  • The potential energy at height h = P.E = 6.381\times 10^{-21} J
  • Molar mass of nitrogen gas =  28.0134 g/mol
  • Mass of nitrogen gas molecule = m

m= \frac{ 28.0134 g/mol}{6.022\times 10^{23} mol^{-1}}=4.652\times 10^{-23} g\\\\1g=0.001kg\\\\m=4.652\times 10^{-23}\times 0.001 kg\\\\=4.652\times 10^{-26} kg

  • The acceleration due to gravity = g = 9.8 m/s^2
  • The maximum height attained by nitrogen gas molecule = h
  • The potential energy is given by:

P.E=mgh

6.381\times 10^{-21} J=4.652\times 10^{-26} kg\times 9.8 m/s^2\times h\\\\h=\frac{6.381\times 10^{-21} J}{4.652\times 10^{-26} kg\times 9.8 m/s^2}\\\\h=13,996.6 m\\\\1 m = 0.001 km\\\\h=13,996.6 m=h=13,996.6\times 0.001 k m\\\\=13.9966 km \approx 14 km

The maximum height at which nitrogen molecule will go before coming to rest is 14 kilometers.

Learn more about the average kinetic energy of gas particles here:

brainly.com/question/16615446?referrer=searchResults

brainly.com/question/6329137?referrer=searchResults

6 0
3 years ago
Mexico City has an elevation of 7400 ft above sea level. Its normal atmospheric pressure is 589 mm Hg. At what temperature does
IRISSAK [1]
Given that the volume and amount  of water are kept constant,
P/T = constant
P₁/T₁ = P₂/T₂
Normal atmospheric pressure is 746 mmHg and normal boiling point of water is 100 °C.
746/100 = 589/T₂
T₂ = 79.0 °C
5 0
3 years ago
How many particles are there in 5.0 moles​
grigory [225]

Answer:

3.01 × 10^24 particles

Explanation:

According to Avagadro, in one mole of a substance, there are 6.02 × 10^23 atoms or particles.

Using the formula: N = n × NA

Where;

N= number of particles or atoms

n = number of moles

NA = Avagadro's constant or number

This means that for 5 moles of a substance, there will be:

5 × 6.02 × 10^23

= 30.1 × 10^23

= 3.01 × 10^24 particles

8 0
3 years ago
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