Question

0.5kg ball moving at a speed of 3m/s rolls up a hill what is thet height

Answer 1

Answer:

0.459 m.

Explanation:

To calculate the height, use 3rd equation of motion as

$v^2-u^2=2gh$

Here v is the final velocity, u is the initial velocity, g is the acceleration due to gravity and h is the height.

As ball moving up so acceleration due to gravity becomes negative i.e -g and at maximum height v = 0.

Therefore equation becomes,

$u=\sqrt{2gh}$

Given u = 3 m/s and g = 9.8 m/s^2.

Substitute the given values, we get

$(3m/s)^2=2\times9.8m/s^2h$

h = 0.459 m

Thus, the height of hill is 0.459 m.