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Leviafan [203]
2 years ago
7

She wanted to find out if a fluorescent lightbulb generated less heat in a room than a standard lightbulb. She formed a hypothes

is and planned out an experiment. She selected one standard lightbulb and one fluorescent lightbulb, making sure that both bulbs gave the same amount of light. Next, she put each lightbulb in a cardboard box (used to represent a room), taped the boxes shut, and measured the temperature change in each box after 30 minutes. She also measured the temperature change with no lightbulb. She repeated each step again to make sure her findings were the same the second time and recorded her measurements in the table below. After looking at the results, she was amazed at what a huge difference there was between the types of bulbs.
which would be the control group? I know the box with the fluorescent light is the experimental group.
Chemistry
1 answer:
daser333 [38]2 years ago
6 0
<span>The box with no lightbulb is the control group. The others are treatments. The purpose of a control group is used to increase the validity of the experiment by testing the independent variable to check that it does not influence the results. </span>




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Water has a slight negative charge around its oxygen atom, and a slight positive charge around its hydrogen atoms Which type of
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A solution is made by mixing equal masses of methanol, CH 4 O , and ethanol, C 2 H 6 O . Determine the mole fraction of each com
Fynjy0 [20]

Answer:

Mole fraction of CH_4O = 0.58

Mole fraction of C_2H_6O = 0.42

Explanation:

Let the mass of CH_4O and C_2H_6O = x g

Molar mass of CH_4O = 33.035 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles_{CH_4O}= \frac{x\ g}{33.035\ g/mol}

Moles_{CH_4O}=\frac{x}{33.035}\ mol

Molar mass of C_2H_6O = 46.07 g/mol

Thus,

Moles= \frac{x\ g}{46.07\ g/mol}

Moles_{C_2H_6O}=\frac{x}{46.07}\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ CH_4O=\frac {n_{CH_4O}}{n_{CH_4O}+n_{C_2H_6O}}

Mole\ fraction\ of\ CH_4O=\frac{\frac{x}{33.035}}{\frac{x}{33.035}+\frac{x}{46.07}}=0.58

Mole fraction of C_2H_6O = 1 - 0.58 = 0.42

6 0
3 years ago
How many moles are in 1.51 x 10^24 molecules of water?
lyudmila [28]

Answer:One mole of HBr has 6.02 x 1

0

23

molecules of HBr.

1 mole of HBr = 6.02 x 1

0

23

molecules of HBr.-----(a)

X mole of HBr has 1.21 x

10

24

molecules of HBr.

X mole of HBr = 1.21 x

10

24

molecules of HBr------(b)

Taking ratio of (a) and (b)

X / 1 = 1.21 x

10

24

/ 6.02 x 1

0

23

X= 2.009 moles.

Explanation:

3 0
3 years ago
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