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o-na [289]
3 years ago
8

Help Me Please The ink is a mixture. Question 5 options: A) True B) False

Chemistry
1 answer:
xeze [42]3 years ago
4 0

Answer:TRUE

Explanation:

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The density of silver is 10.5 g/cm3. A piece of silver that occupies a volume of 42.5 cm3 would have a mass of ________ g.
tia_tia [17]
M=D*V
D=10.5 g/cm³
V=42.5 cm³
m= 10.5 g/cm³ * 42.5 cm³ ≈ 446 g
m≈446 g
8 0
4 years ago
Read 2 more answers
If you are given time and distance, you can determine power if you know
qwelly [4]

Answer:

Yeah force

Yeah Energy

Yeah Watts

Yeah Joules

Explanation:

1. (Force * distance) /time = Power

2. Energy/time = Power

3. Cause Watts = Power

4. Joules is just the unit of energy

7 0
3 years ago
. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the
Anna [14]

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

\frac{P}{T}=k

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

\frac{P1}{T1} =\frac{P2}{T2}

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

  • P1= 0.450 atm
  • T1= 20 C= 293.15 K (being 0 C= 273.15 K)
  • P2=0.750 atm
  • T2= ?

Replacing:

\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}

Solving:

T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }

T2=\frac{0.750 atm}{0.450 atm} *293.15K

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

<u><em>The final temperature of sulfur dioxide gas is 215.43 C</em></u>

6 0
3 years ago
Magnesium reacts with hydrochloric acid to produce magnesium chloride and hydrogen gas. Write a balanced chemical equation for t
Alona [7]

Answer:

The balanced chemical equation is Mg + 2HCl ⇒ MgCl2 + H2

The molarity of the hydrochloric acid solution is HCl 0.04 M and the pH = 1.4.

The volume of hydrogen gas produced by the reaction of 0.510 g of Mg will be 0.482 L.

Explanation:

First, for the balanced equation you have to consider the oxidation state of the elements to find subscripts. Then you can find the correct coeficients. Mg= +2, Cl = -1.

Mg + HCL ⇒ MgCl2 + H2

For the molarity of the solution you have to notice tha if 0.510 grams of Mg reacts with 0,5 L of hydroclhoric acid, and from the previous equation 1 mol of Mg reacts with 2 mol HCl.

The atomic mass of Mg = 24.31 grs/mol

24.31 grs------------ 1 mol Mg

0.510 grs------------ x=0.02 mol Mg.

If 1 mol of Mg reacts with 2 mol HCl, then 0.02 mol of Mg will react with

0.04 mol HCl. So, the molarity of the solution is 0.04 M HCl.

Then to calculate the pH we use the formula pH = - log [H+]

⇒ pH = -log [0.04]⇒ pH=1.4.

Finally, from the balanced equation and the findings described, and considering that at 25°C and 1.00 atm 1 mol of gas has volume of 24.1 L.

1 mol H2----------- 24.1 L

0.02 mol H2----- x= 0.482L.

3 0
4 years ago
The decomposition of dinitrogen pentoxide, N2O5, to NO2 and O2 is a first-order reaction. At 60°C, the rate constant is 2.8 × 10
Ugo [173]

Answer:

The correct option is a.

Explanation:

2N_2O_5\rightarrow 4NO_2 + O_2

125 kPa

125kpa - 2x                            4x    x

Total pressure after reaction = 176 kPa

125 kPa - 2x + 4x + x = 176 kPa

x = 17

125 kpa - 2x = 125 kPa - 2(17) = 91 kPa

Initial pressure of the dinitrogen pentoxide ,(at t=0) =P_o= 125 kPa

Final pressure of the dinitrogen pentoxide, (at t = t) = P = 91 kPa

The rate constant is = k = 2.8\times 10^{-3} min^{-1}

t=\frac{2.303}{k}\log\frac{P_o}{P}

t=\frac{2.303}{2.8\times 10^{-3} min^{-1}}\log\frac{125 kPa}{91 kPa}

t=113.3969 minutes\approx 113 minutes

It will take 113 minutes for the total pressure to reach 176 kPa.

8 0
3 years ago
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