how many grams of solid silver nitrate would you need to prepare 200.0 mL of a 0.150 M AgNO3 solution
1 answer:
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Answer : The mass of produced is, 7.74 grams
Solution : Given,
Mass of = 13.3 g
Molar mass of = 227 g/mole
Molar mass of = 44 g/mole
First we have to calculate the moles of .
Now we have to calculate the moles of
The balanced chemical reaction is,
From the reaction, we conclude that
As, 4 mole of react to give 12 mole of
So, 0.0586 moles of react to give
moles of
Now we have to calculate the mass of
Thus, the mass of produced is, 7.74 grams