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timama [110]
2 years ago
7

Refer to the attached image!!!​

Physics
1 answer:
dimaraw [331]2 years ago
6 0

The time of motion of the track star is determined as 0.837 s.

<h3>Time of motion of the track star</h3>

The time of motion of the track star is calculated as follows;

T = (2u sinθ)/g

where;

  • T is time of motion
  • g is acceleration due to gravity
  • θ is angle of projection

T = (2 x 12 x sin20)/9.8

T = 0.837 s

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

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A 190 g air-track glider is attached to a spring. The glider is pushed in 9.20 cm and released. A student with a stopwatch finds
Sholpan [36]

Answer:

k = 12.136\,\frac{N}{m}

Explanation:

The angular frequency of the system is:

\omega = \sqrt{\frac{k}{m} }

The frequency is:

f = \frac{14\,osc}{11\,s}

f = 1.272\,hz

The angular frequency is:

\omega = 2\pi\cdot (1.272\,hz)

\omega = 7.992\,\frac{rad}{s}

The spring constant is:

k = \left(7.992\,\frac{rad}{s} \right)^{2}\cdot (0.190\,kg)

k = 12.136\,\frac{N}{m}

6 0
3 years ago
A force of 52N acts upon a 4kg block sitting on the ground. Calculate the acceleration of the object.​
irina1246 [14]

Answer:

a=13\ m/s^2

Explanation:

Given that,

Force, F = 52 N

Mass of the block, m = 4 kg

We need to find the acceleration of the object. We know that,

F = ma

Put the values,

a=\dfrac{F}{m}\\\\a=\dfrac{52}{4}\\\\a=13\ m/s^2

So, the acceleration of the object is equal to 13\ m/s^2.

5 0
3 years ago
A projectile is launched from the surface of a planet (mass = 15 x 1024 kg, radius = R = 9.6 x 106 m). What minimum launch speed
Serjik [45]

Answer:

The minimum launch speed is 13366.40 m/s.

Explanation:

Given that,

Mass of planet M=15\times10^{24}\ kg

Radius R= 9.6\times10^{6}\ m

Height = 6R

We need to calculate the speed

Using relation between gravitational force and total energy

-\dfrac{GMm}{6R+R}=\dfrac{1}{2}mv^2-\dfrac{GMm}{R}

\dfrac{}{}mv^2=\dfrac{GMm}{7R}-\dfrac{GMm}{R}

\dfrac{1}{2}mv^2=\dfrac{6GMm}{7R}

v^2=\dfrac{2\times6GM}{7R}

Put the value into the formula

v=\sqrt{\dfrac{2\times6\times6.67\times10^{-11}\times15\times10^{24}}{7\times9.6\times10^{6}}}

v=13366.40\ m/s

Hence, The minimum launch speed is 13366.40 m/s.

6 0
3 years ago
Read 2 more answers
Lake Erie contains roughly 4.00 ✕ 1011 m3 of water. (a) How much energy is required to raise the temperature of that volume of w
denis-greek [22]

Answer:

Part a)

Q = 6.36 \times 10^{18} J

Part b)

t = 144.11 years

Explanation:

Part a)

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Q = ms\Delta T

here we know that

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V = 4.00 \times 10^{11} m^3

now the mass of water is

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now the heat required is

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As we know that power is supplied at

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P = \frac{Q}{t}

so here we have

t = \frac{Q}{P}

t = \frac{6.36 \times 10^{18}}{1400 \times 10^6}

t = 4.54 \times 10^9 s

t = 144.11 years

7 0
3 years ago
Whenever a charged particle encounters a magnetic field, the particle tends to spiral around the magnetic field lines. as it doe
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