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Naddika [18.5K]

4 years ago

11

I feel really isolated these days and wish I had more friends. I've chosen to put myself in new social situations to try to make

new friends. This shows I embrace which model of motivation?
approach
Lack of motivation
avoidance
Behaviorist approach to psychology

1 answer:

leva [86]4 years ago

3 0

Behaviorist approach to psychology

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An egg is Free Falling Down from a nest in a tree (neglect air resistance)

DedPeter [7]

We are to calculate the acceleration.

Answer:

-9.8 m/s²

Explanation:

Since the egg is in a free fall, it means that the force due to gravity will be equal to the normal force.

Now,

Force due to gravity: F_g = mg

Normal force; F_n = ma

Thus;

mg = ma

m will cancel out to get

g = a

Since it is a free fall motion, then gravity is negative;

-g = a

g has a constant value of 9.8 m/s². Thus;

a = -9.8 m/s²

5 0

3 years ago

Olenka [21]

C - I’m pretty sure!

7 0

3 years ago

How fast must a 2500-kg elephant move to have the same kinetic energy as a 67.0-kg sprinter running at 15.0 m/s

abruzzese [7]

Answer:

2.45 m/s

Explanation:

kinetic energy = 1/2 * m * v^2

then, 0.5 * 2500 * x^2 = 0.5 * 67 * 15^2

by solving for x, X = 2.45 m/s

6 0

3 years ago

The measure of an angle is 4y°. Find the measure of its supplement. A) (180 + 4y)° B) (180 - 4y)° C) (90 + 4y)° D) (90 - 4y)°

Viefleur [7K]

Answer: [B]: " (180 <span>- 4y)° " .
_______________________________________________________</span>

3 0

3 years ago

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Two parallel slits are illuminated by light composed of two wavelengths. Wavelength A is 564 nm and the other is wavelength B an

anygoal [31]

Answer:

423nm

Explanation:

To find the unknown wavelength you take into account the distance y to the maximum central fringe, for light fringes and dark fringes.

- for light fringes:

$dsin\theta=m\lambda\\\\sin\theta\approx\theta=\frac{y}{D}\\\\y=\frac{m\lambda_1D}{d}$

- for dark fringes:

$y=\frac{m\lambda_2/2 D}{d}$

The third-order bright fringe (m= 3) of wavelength A coincides with the fourth dark fringe (m=4) of the wavelength B. Hence you have that:

$\frac{(3)\lambda_1D}{d}=\frac{(4)\lambda_2D}{d}\\\\\lambda_2=\frac{3}{4}\lambda_1=\frac{3}{4}(564nm)=423nm$

hence, the wavelength B is 423nm

7 0

4 years ago

Read 2 more answers