Answer:
A) 3.17 g of Zn
Explanation:
Let's consider the reduction of Zn(II) that occurs in an electrolysis bath.
Zn⁺²(aq) + 2e⁻ → Zn(s)
We can establish the following relations:
- 1 min = 60 s
- 1 A = 1 C/s
- The charge of 1 mole of electrons is 96,468 C (Faraday's constant).
- When 2 moles of electrons circulate, 1 mole of Zn is deposited.
- The molar mass of Zn is 65.38 g/mol
The mass of Zn deposited under these conditions is:

Explanation:
Let the volume of the solution be 100 ml.
As the volume of glycol = 50 = volume of water
Hence, the number of moles of glycol = 
= 
= 
= 0.894 mol
Hence, number of moles of water = 
= 2.77
As glycol is dissolved in water.
So, the molality = 
= 17.9
Therefore, the expected freezing point = 
= 
Thus, we can conclude that the expected freezing point is
.
A. SO2Cl2(g) --> SO2(g) + Cl2(g)
<span>1 mole of SOCl2 becomes 1 mole SO2 and 1 mole Cl2 </span>
<span>1 mole --> 2 moles </span>
<span>entropy increases </span>
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