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Answer:
44.8L of hydrogen gas
Explanation:
The reaction expression is given as:
2Na + 2H₂O → 2NaOH + H₂
Given parameters:
Mass of sodium = 92.4g
Unknown:
Volume of hydrogen gas = ?
Solution:
To solve this problem:
1 mole of a substance at STP occupies a volume of 22.4L
Let us find the number of moles of the hydrogen gas;
Number of moles of Na =
Molar mass of Na = 23g/mol
Number of moles = = 4.02mole
From the balanced reaction expression:
2 mole of Na will produce 1 mole of hydrogen gas
4.02 mole of Na will produce = 2mole of hydrogen gas
So
1 mole of a substance at STP occupies a volume of 22.4L
2 mole of hydrogen gas will occupy a volume of 2 x 22.4 = 44.8L of hydrogen gas
Answer:
Three
Explanation:
1. Draw a Lewis structure
- Put the least electronegative atom (C) in the centre
- Attach the O and two S atoms to the C.
- Add enough electrons to give each atom an octet.
2. Draw the resonance structures
You should get one of the structures below.
It has a double bond and two single bonds.
The resonance structures will have the double bond in each of the other two positions.
