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3 years ago

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The mass of jupiter is 300 times the mass of the earth. Jupiter orbits the sun with Tjupiter = 11.9 yr in an orbit with Rjupiter

= 5.2 Rearth. Suppose the earth could be moved to the distance of Jupiter and placed in a circular orbit around the sun. Which of the following describes the earth's new period? EXPLAIN
a) 1 yr
b) between 1 yr and 11.9 yr
c) 11.9 yr
d) more than 11.9 yr
e) It would depend on the earth's speed.
f) It's impossible for a planet of earth's mass to orbit at the distance of Jupiter.

1 answer:

mihalych1998 [28]3 years ago

5 0

Answer:

c) 11.9 yr

Explanation:

The orbital period is proportional to r^(3/2) and does not depend on the satellite's mass. Any object at Jupiter position will have the same orbital period regardless of mass.

By keppler's law we know that

T^2= r^3

T= orbital time period

r= mean distance of the planet from the Sun.

clearly, The orbital period does not depend on the satellite's mass

there, the correct answer will be c= 11.9 yr.

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Answer:

The ball would have landed 3.31m farther if the downward angle were 6.0° instead.

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In order to solve this problem we must first start by doing a drawing that will represent the situation. (See picture attached).

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we pick the positive one, so it takes 0.317s for the ball to hit on point A.

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$x_{A}=V_{Ax}t$

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$y_{Bf}=y_{B0}+V_{0}t-\frac{1}{2}at^{2}$

$0=2.1m+(-2.195m/s)t-\frac{1}{2}(-9.8m/s^{2})t^{2}$

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$t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

$t=\frac{-(-2.195)\pm\sqrt{(-2.195)^{2}-4(-4.9)(2.1)}}{2(-4.9)}$

t= -0.9159s or t=0.468s

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$x_{B}=(20.88m/s)(0.468s)$

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So once we got the two distances we can now find the difference between them:

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