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Irina-Kira [14]
3 years ago
6

Formation of hydrogen bonds requires hydrogen atoms and what else?

Physics
1 answer:
ohaa [14]3 years ago
8 0

Answer:

either a Nitrogen atom, Oxygen atom, or a Flourine atom

Explanation:

The atom has to be more electronegative than hydrogen for the bond to form.

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Which of the following rocks would most likely be found on the ocean floor
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Is there a graph or a picture
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How to tackle questions on resultant force​
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February. we will be in the future types, I

Explanation:

Collins the best year fixed come in handy when but it at a very nice relaxing. it will not have the option?

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When you walk across the ground and push on it with your feet...
marissa [1.9K]

Answer:

The ground pushes back on your feet with equal force.

Explanation:

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You are standing at the top of a cliff that has a stairstep configuration. There is a vertical drop of 7 m at your feet, then a
Zolol [24]

Answer:

1. v = 6.67 m/s

2. d = 9.54 m

Explanation:

1. To find the horizontal velocity of the rock we need to use the following equation:

d = v*t \rightarrow v = \frac{d}{t}    

<u>Where</u>:

d: is the distance traveled by the rock

t: is the time

The time can be calculated as follows:

t = \sqrt{\frac{2d}{g}}

<u>Where:</u>

g: is gravity = 9.8 m/s²

t = \sqrt{\frac{2d}{g}} = \sqrt{\frac{2*7 m}{9.8 m/s^{2}}} = 1.20 s

Now, the horizontal velocity of the rock is:

v = \frac{d}{t} = \frac{8 m}{1.20 s} = 6.67 m/s      

Hence, the initial velocity required to barely reach the edge of the shell below you is 6.67 m/s.          

2. To calculate the distance at which the projectile will land, first, we need to find the time:

t = \sqrt{\frac{2d}{g}} = \sqrt{\frac{2*(7 m + 3 m)}{9.8 m/s^{2}}} = 1.43 s

So, the distance is:

d = v*t = 6.67 m/s*1.43 s = 9.54 m    

Therefore, the projectile will land at 9.54 m of the second cliff.

I hope it helps you!        

7 0
3 years ago
What is the SI unit for kinetic energy
trapecia [35]
The easiest way to build a unit for energy is to remember that
'work' is energy, and  
                                       Work = (force) x (distance).

So energy is                   (unit of force) x (unit of distance)

                   [Energy]  =       (Newton)            (meter) .

'Newton' itself is a combination of base units, so
energy is really
                             (kilogram-meter/sec²)      (meter)

                       =           kilogram-meter² / sec² .

That unit is so complicated that it's been given a special,
shorter name:
                                       Joule .

It doesn't matter what kind of energy you're talking about.
Kinetic, potential, nuclear, electromagnetic, food, chemical,
muscle, wind, solar, steam ... they all boil down to Joules.

And if you generate, use, transfer, or consume 1 Joule of
energy every second, then we say that the 'power' is '1 watt'.
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3 years ago
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