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3 years ago

How far can a sound wave travel in 90 seconds when the ambient air temperature is 10 C?

Physics

1 answer:

Ksju [112]3 years ago

6 0

Answer:

s = 30330.7 m = 30.33 km

Explanation:

First we need to calculate the speed of sound at the given temperature. For this purpose we use the following formula:

v = v₀√[T/273 k]

where,

v = speed of sound at given temperature = ?

v₀ = speed of sound at 0°C = 331 m/s

T = Given Temperature = 10°C + 273 = 283 k

Therefore,

v = (331 m/s)√[283 k/273 k]

v = 337 m/s

Now, we use the following formula to calculate the distance traveled by sound:

s = vt

where,

s = distance traveled = ?

t = time taken = 90 s

Therefore,

s = (337 m/s)(90 s)

s = 30330.7 m = 30.33 km

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what is magnetic field?

Magnetic field is defined as the relationship between the permittivity of free space,the magnitude of electric current,and distance.

Here is the formula,

$B = \frac{µ0l }{2π R}$

here,

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Now,using above formula we can calculate the magnetic field

$B = \frac{µ0l }{2π R}$

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Thus,the magnetic field is

$= 2.288 \times 10 {}^{ - 6} T$

learn more about magnetic field from here: brainly.com/question/28326849

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