Which isotope is use to date ancient artifacts such as fossils?

Monochromatic light with a wavelength of 6.4 E -7 meter passes through two narrow slits, producing an interference pattern on a

seropon [69]

Answer:

The distance between the slits is given by 1.3 × $10^{-4}$ m

Given:

$\lambda = 6.4 \times 10^{-7} m$

D = 4 m

y = $2 \times 10^{-2} m$

m = 1

To find:

distance between slits, d = ?

Formula used:

y = $\frac{m \times \lambda \times D}{d}$

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

$\lambda$ = wavelength

Solution:

distance of first bright band from central maxima is given by,

y = $\frac{m \times \lambda \times D}{d}$

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

$\lambda$ = wavelength

Thus,

d = $\frac{m \times \lambda \times D}{y}$

d = $\frac{1 \times 6.4 \times 10^{-7} \times 4 }{2 \times 10^{-2} }$

d = 1.28 × $10^{-4}$

d = 1.3 × $10^{-4}$ m

The distance between the slits is given by 1.3 × $10^{-4}$ m

8 0

3 years ago

A pot of black eyed peas heats to a boil on the stove. The boiling peas is a model of

eduard

Radiation, convection, conduction, efficiency

8 0

3 years ago

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A planet is 10 light years away from Earth. What speed would you need to go for a trip to the planet and back to take only 5 yea

viva [34]

Answer:

a. speed, v = 0.97 c

b. time, t' = 20.56 years

Given:

t' = 5 years

distance of the planet from the earth, d = 10 light years = 10 c

Solution:

(a) Distance travelled in a round trip, d' = 2d = 20 c = L'

Now, using Length contraction formula of relativity theory:

$L'' = L'\sqrt{1 - \frac{v^{2}}{c^{2}}}$ (1)

time taken = 5 years

We know that :

time = $\frac{distance}{speed}$

5 = $\frac{L''}{v}$ (2)

Dividing eqn (1) by v on both the sides and substituting eqn (2) in eqn (1):

$\frac{L'\sqrt{1 - \frac{v^{2}}{c^{2}}}}{v} = 5$

$\frac{20'\sqrt{1 - \frac{v^{2}}{c^{2}}}}{v} = 5$

Squaring both the sides and Solving above eqution, we get:

v = 0.97 c

(b) Time observed from Earth:

Using time dilation:

$t'' = \frac{t'}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$

$t'' = \frac{5}{\sqrt{1 - \frac{(0.97c)^{2}}{c^{2}}}}$

Solving the above eqn:

t'' = 20.56 years

4 0

3 years ago

A spring is stretched 6 m when a mass of 20kg is hung on it. Calculate the spring constant of this spring

tresset_1 [31]

The spring constant of this spring is 9810 N/m.

<h3>What is spring constant?</h3>

Hooke's law states that the force (F) needed to extend a spring is proportional to the distance from the equilibrium position of spring.

F =kx

where k is the constant of proportionality called spring constant.

As, the mass attached with the spring is hung, then the force is equal to the weight (W).

F = W

So, kx =mg

Substituting W = mg into equation (ii) above, we have

F = mg

Substituting F = mg into equation (i) above, we have

mg = kx

Substitute, extension x = 2cm = 0.02m, mass m= 40g = 0.04kg, g is the acceleration due to gravity =9.81m/s²

Substituting these values into equation, we have

k = 20 x 9.81 /0.02

k = 9810 N/m

Therefore, the spring constant is k = 9810 N/m.

Learn more about spring constant.

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8 0

2 years ago

How do heavy airplanes fly?

Marat540 [252]

With thier wings and an engine how else

4 0

3 years ago

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