Answer:
1.395M NaOH
Explanation:
Sodium hydroxide, NaOH, reacts with nitric acid, HNO3, as follows:
NaOH + HNO3 → NaNO3 + H2O
<em>Where 1mol of NaOH reacts with 1mol of HNO3</em>
To solve this question we must find the concentration of the titrant. With the concentration and the needed acid we can find the moles of HNO3 added = moles NaOH in the solution. With the moles of NaOH and its volume we can find its concentration as follows:
<em>HNO3 concentration:</em>
10.00mol/L HNO3 * (125.0mL/500.0mL) = 2.500M HNO3
<em>Moles HNO3 = Moles NaOH:</em>
16.74mL = 0.01674L*(2.500mol/L) = 0.04185 moles HNO3 = Moles NaOH
<em>Concentration NaOH:</em>
0.04185 moles / 0.0300L =
1.395M NaOH
Answer:
B is the answer
Explanation:
B is the most un reasonable answer to do at the BEGINNING of the process. All of the other answers are things you do at the beginning or, before you start it. "Decide whether they have designed the best possible product" means you FINISHED it already, and we want what the engineers needs to do at the beginning. Common sense actually. Your welcome.
<em>A friendly dude that likes to help</em>
B. Water Temperature {A PE X}
Explanation:
Hello!
The force on the student is equal to the force the student exerts, so 100N is your answer.
Hope this helped :))
Answer:
Mass = 36 g
Explanation:
Given data:
Mass of water formed = ?
Mass of hydrogen = 4.04 g
Mass of oxygen = 31.98 g
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass/molar mass
Number of moles = 4.04 g/ 2 g/mol
Number of moles = 2.02 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 31.98 g/ 32 g/mol
Number of moles = 1.0 mol
Now we will compare the moles of water with hydrogen and oxygen.
O₂ : H₂O
1 : 2
H₂ : H₂O
2 : 2
2.02 : 2.02
Number of moles of water formed by oxygen are less thus oxygen will limiting reactant.
Mass of water:
Mass = number of moles × molar mass
Mass = 2 mol × 18 g/mol
Mass = 36 g
