Answer:
166.8 m
30.18 m/s
Explanation:
u = Velocidad inicial del automóvil = 120 km/h = ![\dfrac{120}{3.6}=33.33\ \text{m/s}](https://tex.z-dn.net/?f=%5Cdfrac%7B120%7D%7B3.6%7D%3D33.33%5C%20%5Ctext%7Bm%2Fs%7D)
v = Velocidad final = 0
s = Desplazamiento
a = Aceleración
t = Tiempo tomado = 10 s
De las ecuaciones cinemáticas de movimiento tenemos
![v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-33.33}{10}\\\Rightarrow a=-3.33\ \text{m/s}^2](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20a%3D%5Cdfrac%7Bv-u%7D%7Bt%7D%5C%5C%5CRightarrow%20a%3D%5Cdfrac%7B0-33.33%7D%7B10%7D%5C%5C%5CRightarrow%20a%3D-3.33%5C%20%5Ctext%7Bm%2Fs%7D%5E2)
![v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-33.33^2}{2\times -3.33}\\\Rightarrow s=166.8\ \text{m}](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20s%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2a%7D%5C%5C%5CRightarrow%20s%3D%5Cdfrac%7B0-33.33%5E2%7D%7B2%5Ctimes%20-3.33%7D%5C%5C%5CRightarrow%20s%3D166.8%5C%20%5Ctext%7Bm%7D)
La distancia que tarda el automóvil en detenerse es 166.8 m
Ahora s = 30 m
![v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -3.33\times 30+33.33^2}\\\Rightarrow v=30.18\ \text{m/s}](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2as%2Bu%5E2%7D%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2%5Ctimes%20-3.33%5Ctimes%2030%2B33.33%5E2%7D%5C%5C%5CRightarrow%20v%3D30.18%5C%20%5Ctext%7Bm%2Fs%7D)
La velocidad a la que el otro automóvil sería golpeado es 30.18 m/s.
Answer:
0.050V
Explanation:
To solve this problem it is necessary to use the concepts related to the potential between two objects that have a magnetic field, this concept is represented in the equation.
![\int dV = \int_{0}^{l/2} Bv (dl)](https://tex.z-dn.net/?f=%5Cint%20dV%20%3D%20%5Cint_%7B0%7D%5E%7Bl%2F2%7D%20Bv%20%28dl%29)
Where,
v= tangencial velocity
B = Magnetic Field
We know for definition that,
![v= l\omega](https://tex.z-dn.net/?f=v%3D%20l%5Comega)
Where,
L = length
Angular velocity
We can replace this values in our first equation then,
![\int dV = \int_{0}^{l/2} B (l\omega) (dl)](https://tex.z-dn.net/?f=%5Cint%20dV%20%3D%20%5Cint_%7B0%7D%5E%7Bl%2F2%7D%20B%20%28l%5Comega%29%20%28dl%29)
Integrating we have,
![V = \frac{1}{8} Bl^2 \omega](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B8%7D%20Bl%5E2%20%5Comega)
Replacing the values,
![V= \frac{1}{8} (8*10^{-3})(12.56)(4)](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B1%7D%7B8%7D%20%288%2A10%5E%7B-3%7D%29%2812.56%29%284%29)
![V = 0.050V](https://tex.z-dn.net/?f=V%20%3D%200.050V)
Therefore the potential difference between the center of the rod and the other rod is 0.050V
Answer:
That people are motivated by a series of five universal needs.
Explanation:
The variety of species in an ecosystem is known as biodiversity.
The free energy change for generating the electrical imbalance of protons in respiring mitochondria in culture will be 14.5 kJ/mol.
<h3>What is free energy?</h3>
Free energy is the greatest amount of non-expansion work that a closed system can extract.
The free energy change for generating the electrical imbalance of protons is found as;
![\rm \triangle G = ZF \triangle \psi\ \\\\ \triangle G =1 \times 96485 \times 0.150\\\\ \triangle G= 14.5 \ kJ/mol](https://tex.z-dn.net/?f=%5Crm%20%5Ctriangle%20G%20%3D%20ZF%20%5Ctriangle%20%5Cpsi%5C%20%5C%5C%5C%5C%20%20%5Ctriangle%20G%20%3D1%20%5Ctimes%2096485%20%5Ctimes%200.150%5C%5C%5C%5C%20%5Ctriangle%20G%3D%2014.5%20%5C%20kJ%2Fmol)
Hence,the free energy change for generating the electrical imbalance of protons in respiring mitochondria in culture will be 14.5 kJ/mol.
To learn more about the free energy, refer:
brainly.com/question/15319033
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