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trapecia [35]
3 years ago
7

Mr. McPhillip has a ribbon of magnesium (Mg), a silvery metal. As a demonstration for his class, he sets the metal on fire. It b

urns brightly, leaving behind a whitish powder.
Mr. McPhillip has a ribbon of magnesium (Mg), a silvery metal. As a demonstration for his class, he sets the metal on fire. It burns brightly, leaving behind a whitish powder.

The magnesium is a(n) _______, and the powder produced by burning it is a(n) _______.
A.
element; compound
B.
compound; compound
C.
compound; element
D.
element; element
Chemistry
2 answers:
ICE Princess25 [194]3 years ago
8 0
Magnesium is an element and magnesium oxide is a compound, so Answer A.
OLEGan [10]3 years ago
5 0
A. Magnesium is an element and after it is burned it is a compound
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The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react
Kazeer [188]

Answer:

The percent yield of  chloro-ethane in the reaction is 82.98%.

Explanation:

C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl

Moles of ethane = \frac{300.0 g}{30 g/mol}=10 mol

Moles of chlorine gases =\frac{650.0 g}{71 .0 g/mol}=9.1549 mol

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

\frac{1}{1}\times 9.1549 mol=9.1549 mol of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of  chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%

The percent yield of  chloro-ethane in the reaction is 82.98%.

6 0
3 years ago
Carbon dating requires that the object being tested contain
luda_lava [24]

Answer:

Organic Material

Explanation:

Carbon Dating is the process in which the age of a piece of organic matter is determined by the proportions of carbon isotopes it contains.

4 0
2 years ago
How many moles are there in 8.94*10^24 atoms P?
IgorC [24]

Answer:

<h2>14.85 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.94 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\   = 14.850498

We have the final answer as

<h3>14.85 moles</h3>

Hope this helps you

7 0
2 years ago
Read 2 more answers
If an equal number of moles of reactants are used, do the following equilibrium mixtures contain primarily reactants or products
puteri [66]

<u>Answer:</u>

<u>For a:</u> The equilibrium mixture contains primarily reactants.

<u>For b:</u> The equilibrium mixture contains primarily products.

<u>Explanation:</u>

There are 3 conditions:

  • When K_{eq}>1; the reaction is product favored.
  • When K_{eq}; the reaction is reactant favored.
  • When K_{e}=1; the reaction is in equilibrium.

For the given chemical reactions:

  • <u>For a:</u>

The chemical equation follows:

HCN(aq.)+H_2O(l)\rightleftharpoons CN^-(aq.)+H_3O^+(aq.);K_{eq}=6.2\times 10^{-10}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[CN^-][H_3O^+]}{[HCN][H_2O]}=6.2\times 10^{-10}

As, K_{eq}, the reaction will be favored on the reactant side.

Hence, the equilibrium mixture contains primarily reactants.

  • <u>For b:</u>

The chemical equation follows:

H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g);K_{eq}=2.51\times 10^{4}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[HCl]^2}{[H_2][Cl_2]}=2.51\times 10^{4}

As, K_{eq}>1, the reaction will be favored on the product side.

Hence, the equilibrium mixture contains primarily products.

4 0
3 years ago
5. An object is a regular, rectangular, solid with dimensions of 2 cm by 3cm by 2cm. It has a mass of 24 g. find its density.
m_a_m_a [10]

Answer:

Density, D = 2g/cm^3

Explanation:

Given the following data;

Length = 2cm

Width = 3cm

Height = 2cm

Mass = 24g

Density = ?

Volume of a rectangular solid (V) = Length × Weight × Height

Therefore, V = L× W × H

Substituting the values, we have;

V = 2 *3 * 2 = 12

V = 12cm

Density can be defined as the ratio of mass to volume i.e mass all over volume.

Mathematically, Density = \frac{Mass}{Volume}

D = \frac{M}{V}

Substituting the values, we have;

D = \frac{24}{12}

<em>Density, D = 2g/cm^3</em>

Hence, the density of the rectangular solid is 2g/cm^3.

3 0
3 years ago
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