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3 years ago

How can magnet be used to produce an electric current

Physics

1 answer:

Bess [88]3 years ago

3 0

Answer:

Magnetic fields can be used to make electricity

Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current. Electricity generators essentially convert kinetic energy (the energy of motion) into electrical energy

Explanation:

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Light traveling through air encounter a second medium which slows the light to 2.7 x 10^8. What is the index of the medium?

kozerog [31]

Answer:

1.11

Explanation:

The index of the medium can be calculated using below formula

V= c/ n ............eqn(1)

Where V= velocity of the light is reduced to while traveling through the second medium= 2.7 x 10^8 m/s

n= index of the medium

c= speed of light= 3 x 10^8 m/s

Substitute for the values in eqn(1)

2.7 x 10^8 = (3 x 10^8 m/s)/ n

Making " n" subject of the formula, we have

n= (3 x 10^8 )/(2.7 x 10^8)

n= 1.11

Hence, the index of the medium is 1.11

5 0

3 years ago

A 300 kg piano needs to be moved to the other side of the room. The maximum static frictional force is equal to 90 N and the kin

riadik2000 [5.3K]

Answer:

a = 0.1 m/s²

Explanation:

If the maximum static frictional force is 90 N, this means that any applied force that will overcome this force, will cause the piano to slide, so kinetic frictional force applies.
Under these conditions, the net force in the horizontal direction is just the difference between the applied force (which is larger that the static friction force) and the kinetic frictional force, as follows:

$F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)$

By the same token, according Newton's 2nd Law, this force is just equal to the product of the mass of the piano, times the acceleration, as follows:

$F_{net} = m* a = 300 Kg * a = 30 N (2)$

Solving for a:

$a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)$

5 0

3 years ago

An air conditioner operating at steady state maintains a dwelling at 70oF on a day when the outside temperature is 90oF. If the

torisob [31]

30000 btuh /3413 btuh/kw. = 8.8 kw

8.8 kw/.746 kw/hp = 11.8 hp if COP is 1

11.8/3 hp (COP coefficient of performance) = 3.99 COP

>>>So yes a 3.0 hp compressor with a nominal COP of 4 will handle the 30,000 btuh load.

3.2 to 4.5 is expected COP range for an air cooled heat pump or a/c unit.

8 0

3 years ago

The Moon and Earth rotate about their common center of mass, which is located about RcM 4700 km from the center of Earth. (This

erica [24]

To solve this problem it is necessary to apply the concepts related to gravity as an expression of a celestial body, as well as the use of concepts such as centripetal acceleration, angular velocity and period.

PART A) The expression to find the acceleration of the earth due to the gravity of another celestial body as the Moon is given by the equation

$g = \frac{GM}{(d-R_{CM})^2}$

Where,

G = Gravitational Universal Constant

d = Distance

M = Mass

$R_{CM} =$ Radius earth center of mass

PART B) Using the same expression previously defined we can find the acceleration of the moon on the earth like this,

$g = \frac{GM}{(d-R_{CM})^2}$

$g = \frac{(6.67*10^{-11})(7.35*10^{22})}{(3.84*10^8-4700*10^3)^2}$

$g = 3.4*10^{-5}m/s^2$

PART C) Centripetal acceleration can be found throughout the period and angular velocity, that is

$\omega = \frac{2\pi}{T}$

At the same time we have that centripetal acceleration is given as

$a_c = \omega^2 r$

Replacing

$a_c = (\frac{2\pi}{T})^2 r$

$a_c = (\frac{2\pi}{26.3d(\frac{86400s}{1days})})^2 (4700*10^3m)$

$a_c = 3.34*10^{-5}m/s^2$

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3 years ago

Since monsoons are storms that usually occur during a specific time of year in certain regions, you could not compare them to th

sweet [91]

In the given statement: "<span>Since monsoons are storms that usually occur during a specific time of year in certain regions, you could not compare them to thunderstorms. </span>" is false. Therefore, among the given choices, the correct answer is B. False.

4 0

3 years ago

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