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Colt1911 [192]
4 years ago
14

What is the volume of 7.50x10^24 molecules of NH3 at STP

Chemistry
1 answer:
Bas_tet [7]4 years ago
4 0

Answer:

V NH3 = 304.334 L

Explanation:

  • 1 mol ≡ 6.02 E23 molecules

⇒ moles NH3 = (7.50 E24 molecules)×(mol/6.022 E23 molecules)

⇒ mole NH3 = 12.454 mol

assuming ideal gas:

  • PV = RTn

STP:

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

⇒ V NH3 = RTn/P

⇒ V NH3 = ((0.082 atm.L/K.mol)×(298 K)×(12.454 mol))/(1 atm)

⇒ V NH3 = 304.334 L

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Answer : The time it take to plate out will be, 3.69 minutes.

Explanation :

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\text{Moles of }Cr}=\frac{\text{Mass of Cr}}{\text{Molar mass of Cr}}

Molar mass of Cr = 51.9 g/mol

\text{Moles of }Cr}=\frac{2.19g}{51.9g/mol}=0.0423mol

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Cr^{3+}+3e^-\rightarrow Cr

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The quantity of charge required for the reduction of 1 mole of Cr^{3+} = 3\times F

The quantity of charge required for the reduction of 0.0423 mole of Cr^{3+} = 0.0423\times 3\times F=0.1269F=0.1269\times 96500C=12245.85C

Now we have to calculate the time taken.

We know that,

q=I\times t

t=\frac{q}{I}=\frac{12245.85C}{55.2A}=221.845s=3.69min

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