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Hitman42 [59]
3 years ago
5

PLEASE HELP

Chemistry
1 answer:
aev [14]3 years ago
6 0

Answer: option C. Kelvin temperature

Explanation:

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Explain the changes that take place at the molecular level when a substance is superheated or supercooled ?
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Only gas or vapor can be superheated. Use water as an example. Water at sea level boils at 212 degrees F. When heated to 212 degrees F, the molecules that make up water are moving at a high enough speed that they overcome the air pressure above the water. And for supercooled only liquids or solids can be supercooled for example Liquid water at sea level has a saturation (boiling) temperature of 212 degrees F. If we were to add heat to the saturated water, it would first boil away with no change in temperature (remember latent heat?) and then become superheated if still more heat were added to the vapor (steam) after it had all turned to a vapor.
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What will occurs during electrolysis of dilute sulphuric acid​
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Answer:

In the electrolysis of dilute sulfuric acid, which electrolysis in aqueous solution to form hydrogen ions, H⁺, and sulfur IV ions SO₄²⁻ in the presence of H⁺ and OH⁻ ions from the water molecules

At the anode

The anode, positive electrode, attracts the negative OH⁻ and SO₄²⁻ ions where the OH⁻ gives up electrons to form water molecules and oxygen as follows;

4OH⁻ → 2H₂O + O₂ + 4e⁻

At the cathode

The positive H⁺ ions from the water molecules and the acid are attracted to the cathode where they combine with 2 electrons to form hydrogen gas as follows;

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Explanation:

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The metal which burns with a white dazzling flame is:
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Answer:

<h3><u>Magnesium</u></h3>

Magnesium burns with a dazzling white flame to form magnesium oxide a powdery mass.

Explanation:

<h2>Hope this helps you !! </h2>
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2 years ago
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1.25 x 1025 molecules of glucose (C H202) is<br> how many moles of glucose?
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A student mixes a solution of lead (II) nitrate with a solution of potassium iodide and notices the formation of a yellow solid.
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Answer:

Lead (II) iodide

Explanation:

The reaction of lead (II) nitrate, Pb(NO₃)₂ with KI is:

Pb(NO₃)₂(aq) + 2KI(aq) → KNO₃(aq) + PbI₂(s)

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All nitrates are solubles, thus, KNO₃ is not the precipitate.

The only possibility of precipitate is PbI₂,

Lead (II) iodide, a yellow and insoluble solid...

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3 years ago
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