Answer: ΔH for the reaction is -277.4 kJ
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
![\Delta H=\sum [n\times \Delta H(products)]-\sum [n\times \Delta H(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%28products%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%28reactant%29%5D)
![\Delta H=[(n_{CCl_4}\times \Delta H_{CCl_4})+(n_{HCl}\times B.E_{HCl}) ]-[(n_{CH_4}\times \Delta H_{CH_4})+n_{Cl_2}\times \Delta H_{Cl_2}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%28n_%7BCCl_4%7D%5Ctimes%20%5CDelta%20H_%7BCCl_4%7D%29%2B%28n_%7BHCl%7D%5Ctimes%20B.E_%7BHCl%7D%29%20%5D-%5B%28n_%7BCH_4%7D%5Ctimes%20%5CDelta%20H_%7BCH_4%7D%29%2Bn_%7BCl_2%7D%5Ctimes%20%5CDelta%20H_%7BCl_2%7D%5D)
where,
n = number of moles
Now put all the given values in this expression, we get
![\Delta H=[(1\times -139)+(1\times -92.31) ]-[(1\times -74.87)+(1\times 121.0]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%281%5Ctimes%20-139%29%2B%281%5Ctimes%20-92.31%29%20%5D-%5B%281%5Ctimes%20-74.87%29%2B%281%5Ctimes%20121.0%5D)
Therefore, the enthalpy change for this reaction is, -277.4 kJ
Answer:
negative, positive, increase
Explanation:
From the given question,
During the formation of bond, between two atoms with difference between their electronegativity-
- The more electronegative atom, will pull the electrons towards itself , and hence acquires a partial negative charge,
And,
- The less electronegative atom, will acquire a partial positive charge.
- The more the difference between the electronegativity of the atoms, the more would be the magnitude of partial charge.
- And, the less would be the difference between the electronegativity of the atoms, the lesser would be the magnitude of partial charge.
It'll beginning to evaporate.
The question is incomplete. Complete question is attached below.
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Correct Answer: <em>Option 1) 2-pentene</em>
Reason:
Following are the IUPAC rules for naming the compound
1) Select the
longest carbon chain. In present case longest carbon chain has 5 carbon atom. Hence, it is a pentane derivative.
2) In case of alkene,
replace 'e' of alkane by 'ene'3) Give
lowest number to function group. In present case, it is double bond.
Applying above rules, the IUPAC name of compound is
2-pentene
Answer:
did you mean moles? If so, answer is down below.
Explanation:
there are 0.106 moles of glucose in 19.1 g of glucose.
