All categories

4 years ago

Question 1 (1 point)

Physics

1 answer:

TiliK225 [7]4 years ago

3 0

Answer:

The resultant velocity of the plane relative to the ground is;

150 kh/h north

Explanation:

The flight speed of the plane = 210 km/h

The direction of flight of the plane = North

The speed at which the wind is blowing = 60 km/h

The direction of the wind = South

Therefore, representing the speed of the plane and the wind in vector format, we have;

The velocity vector of the plane = 210. $\hat j$

The velocity vector of the wind = -60. $\hat j$

Where, North is taken as the positive y or $\hat j$ direction

The resultant velocity vector is found by summation of the two vectors as follows;

Resultant velocity vector = The velocity vector of the plane + The velocity vector of the wind

Resultant velocity vector = 210. $\hat j$ + (-60. $\hat j$ ) = 210. $\hat j$ - 60. $\hat j$ = 150. $\hat j$

The resultant velocity vector = 150. $\hat j$

Therefore, the resultant velocity of the plane relative to the ground = 150 kh/h north.

You might be interested in

What is the maximum kinetic energy of ejected electrons when photons of wavelength 300 nm hit a metal that has a work function o

Sonja [21]

Explanation:

Given that,

Wavelength of the photon, $\lambda=300\ nm=3\times 10^{-7}\ m$

Work function of the metal, $\phi=1.13\ eV=1.81\times 10^{-19}\ J$

We need to find the maximum kinetic energy of the ejected electrons. It can be calculated using Einstein's photoelectric equation as :

$hf=E_k+\phi$

$E_k=hf-\phi$

$E_k=h\dfrac{c}{\lambda}-\phi$

$E_k=6.63\times 10^{-34}\times \dfrac{3\times 10^8}{3\times 10^{-7}}-1.81\times 10^{-19}$

$E_k=4.82\times 10^{-19}\ J$

$E_k=3.01\ eV$

$E_k=3\ eV$

So, the maximum kinetic energy of the ejected electrons is 3 ev. Hence, this is the required solution.

3 0

3 years ago

A famous physics tale is about a rich man who was found dead. He was

anyanavicka [17]

<h2>Answer: C) He could have thrown the bag of money sideways, creating a horizontal reaction force on himself.</h2>

Explanation:

According to Newton's third law of motion, when two bodies interact between them, appear equal forces and opposite senses in each of them.

To understand it better:

Each time a body or object exerts a force on a second body or object, it (the second body) will exert a force of equal magnitude and direction but in the opposite direction on the first.

So, if the rich man had pushed the bag of money horizontally opposite of where he was, he could have saved himself.

7 0

3 years ago

We wish to obtain a equal sized inverted image of a candel flame on a screen kept at a distance of 4m from the candle flame a) n

soldier1979 [14.2K]

A) To obtain an inverted image of an object of same size a convex lens is used.

In this question we have given

Distance between candle flame and screen=4

it means distance between candle flame and lens +distance between lens and screen =4m

u+v= 4m

u= v

therefore, 2u= 4m

or, u=-2m ( u is taken negative because it lies on left side of the lens)

and v=2m

we have to find the focal length of convex lens

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$ $\frac{1}{f} = \frac{1}{2} - ( - \frac{1}{2} ) \\ \frac{1}{f} = \frac{1}{1}\\ f = 1m$

Hence, Focal length of the lens is 1m

and lens should be placed at a distance of 2m from the flame

4 0

3 years ago

Light from a sodium lamp 1l = 589 nm2 illuminates two narrow slits. the fringe spacing on a screen 150 cm behind the slits is 4.

BartSMP [9]

d = 0.221 mm is the spacing (in mm) between the two slits..

here,

wavelength = 589 nm

D = 150 cm = 1.5 m

y = 4 mm

then ,

y = mλD/d

for m = `1

0.004 = 589*10^-9 * 1.5/d

d = 2.21*10^-4 m

d = 0.221 mm

slit spacing is 0.221 mm

The sesmic characteristics of a train depend on the speed of the train, the distance between the wheels, and the hardness of the ground beneath the rails.

Philadelphia attack efficiency aims to improve spacing It continues to lag despite offseason moves, and Harden could have single-handedly fixed these issues.

In a typical hydrogen bond, as atoms move further up the energy ladder, The distance between the energy levels decreases. For Scientists Working at Such Small Scales, these “charging times” are likely candidates for the cause of the distance effect.

Learn more about spacing here:

brainly.com/question/15862947

#SPJ4

7 0

2 years ago

The driver of a pickup truck accelerates from rest to a speed of 37 mi/hr over a horizontal distance of 215 ft with constant acc

ZanzabumX [31]

Answer:

Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf

Explanation:

First we will find the acceleration of pickup truck.

As, the acceleration is uniform, therefore we can use Newton's third equation of motion:

2as = $V_{f}^{2}-V_{i}^{2}$

First convert speed into ft/sec

1 mile/hr = 1.47 ft/sec

therefore,

37 mile/hr = 37 x 1.47 ft/sec

37 mile/hr = 54.39 ft/sec

with initial speed 0 ft/sec (starting from rest), using in equation of motion:

a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)

a = 6.88 ft/sec²

Now, the total shear force will be given by Newton's second law of motion:

F = ma

F = (460 lbm +72 lbm)(6.88 ft/sec²)

F = 3660 lbf

Now for the max shear force in each of the two pegs we divide total fore by 2:

Force in each peg = F/2 = (3660 lbf)/2

<u>Force in each peg = 1830 lbf</u>

6 0

3 years ago