Answer:
107.3 m/s
Explanation:
The motion of Garlit is a uniformly accelerated motion (=constant acceleration), therefore we can use the following suvat equation:
where
u is the initial velocity
v is the final velocity
a is the acceleration
t is the time
In this problem, we have:
u = 0 (Garlit starts from rest)
is the acceleration
Therefore, the final velocity after t = 6.5 s is:
Answer: object B is negatively charged, object C is positively charged and object D is also positively charged
Explanation: since unlike charges attract and like charges repel, for object A which is positively charged and B to attract B must be negatively charged and then for B which is negatively charged and C to attract C must be positively charged and for C and D to repel they have to be of thesame charge which means D is positive as well.
Refer to the diagram shown below.
h = height of the girl above water when she lets go of the rope.
The launch velocity is 22.5 m/s at 35° to the horizontal. Therefore the vertical component of the velocity is
v = 22.5 sin(35°) = 12.9055 m/s.
The time of flight is t = 1.10 s before the girl hits the surface of the water at a height of -h.
Therefore
-h = (12.9055 m/s)*(1.10 s) - (1/2)*(9.8 m/s²)*(1.10 s)²
-h = 8.267 m
= 8.3 m (nearest tenth)
Answer:
When the girl let go of the rope, she was about 8.3 m above the surface of the water.
Answer:A and C
Explanation:i got them correct