Give an example in which there are clear distinctions among distance traveled, displacement, and magnitude of displacement. spec
ifically identify each quantity in your example.
1 answer:
The example I've given is shown as an illustration in the picture. Suppose a jogger covers 2 km as he heads to the east. Then, he heads up north for another 1.5 km. Now, if you are to find the distance, you simply have to take the sum.
Distance = 2 + 1.5 = 3.5 km
If you are to find the displacement, you find the distance from the starting point to the end point, represented by the red arrow. Using the pythagorean theorem,
Displacement = √(2 km)² + (1.5 km)² = 2.5 km
If you are to find the magnitude of displacement, this is equivalent to distance. So, it is equal to 3.5 km. The displacement is a vector quantity, which presents the magnitude and the direction. The magnitude of the displacement does not take into account the direction of motion, just the total distance covered.
Distance = 2 + 1.5 = 3.5 km
If you are to find the displacement, you find the distance from the starting point to the end point, represented by the red arrow. Using the pythagorean theorem,
Displacement = √(2 km)² + (1.5 km)² = 2.5 km
If you are to find the magnitude of displacement, this is equivalent to distance. So, it is equal to 3.5 km. The displacement is a vector quantity, which presents the magnitude and the direction. The magnitude of the displacement does not take into account the direction of motion, just the total distance covered.
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Answer:
W = 0 J
Explanation:
The amount of work done by gas at constant pressure is given by the following formula:
where,
W = Work done by the gas
P = Pressure of the gas
ΔV = Change in the volume of the gas
Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:
<u>W = 0 J</u>