Give an example in which there are clear distinctions among distance traveled, displacement, and magnitude of displacement. spec
ifically identify each quantity in your example.
1 answer:
The example I've given is shown as an illustration in the picture. Suppose a jogger covers 2 km as he heads to the east. Then, he heads up north for another 1.5 km. Now, if you are to find the distance, you simply have to take the sum.
Distance = 2 + 1.5 = 3.5 km
If you are to find the displacement, you find the distance from the starting point to the end point, represented by the red arrow. Using the pythagorean theorem,
Displacement = √(2 km)² + (1.5 km)² = 2.5 km
If you are to find the magnitude of displacement, this is equivalent to distance. So, it is equal to 3.5 km. The displacement is a vector quantity, which presents the magnitude and the direction. The magnitude of the displacement does not take into account the direction of motion, just the total distance covered.
Distance = 2 + 1.5 = 3.5 km
If you are to find the displacement, you find the distance from the starting point to the end point, represented by the red arrow. Using the pythagorean theorem,
Displacement = √(2 km)² + (1.5 km)² = 2.5 km
If you are to find the magnitude of displacement, this is equivalent to distance. So, it is equal to 3.5 km. The displacement is a vector quantity, which presents the magnitude and the direction. The magnitude of the displacement does not take into account the direction of motion, just the total distance covered.
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Answer:
4.3 m/sec
Explanation:
Here height of cliff = y = 37.6 m
Gravitational acceleration = g = 9.8 m/sec2
vi = 0 m/s
Let's find the time which the diver will take if jumps from there!
Using formula
y = vit+1/2gt2
==> 37.6= 0 + 0.5 ×9.8×
==>=
==> t = 2.8 sec
In this time the diver has to cover a horizontal distance of 12.12 m
If x = 12.12 m is the horizontal distance to be covered then using
x= Vx × t
==> Vx = x/t
==> Vx= 12.12/2.8 = 4.3 m/s