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2 years ago

"In regards to the global energy budget, Earth absorbs __ wave radiation and emits _ wave radiation"

Physics

1 answer:

OLga [1]2 years ago

6 0

Answer:

In regards to the global energy budget, Earth absorbs short-wave radiation and emits long-wave radiation.

Explanation:

It is required to tell what kind of wave radiation the earth absorbs and emits in regards to the global energy budget.

Let us discuss the global energy budget first.

The balance between the solar energy that enters Earth and the energy that leaves Earth and travels back into space is known as the global energy budget or the earth's energy budget. The visible region of the electromagnetic spectrum is where the majority of the sun's energy is found.

Therefore earth absorbs short-wave radiation and emits long-wave radiation in regard to the global energy budget.

To know more about, the global energy budget, refer to:

brainly.com/question/4352906

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I need an answer asap

gulaghasi [49]

He has a mass of 56 kg.

The equation given is PE = mgh.

PE = 4620 J

h = 8.4

g = 9.8

Therefore:

4620 = 82.32m

m = 4620/82.32
m = 56 (rounded to two significant digits)

5 0

3 years ago

A 3250 N car is pushed a distance of 35 m the power was 11375 J, how long did it take?

irakobra [83]

Answer:

10.8s

Explanation:

Given parameters:

Force on the car = 3250N

Distance = 35m

Power = 11375W

Unknown:

Time taken = ?

Solution:

To solve this problem;

Power is the rate at which work is done

Power = $\frac{work done }{time}$

Work done = force x distance = 3250 x 35 = 123200J

Now;

11375 = $\frac{123200}{t}$

11375t = 123200

t = 10.8s

5 0

3 years ago

The velocity profile in fully developed laminar flow in a circular pipe of inner radius R 5 2 cm, in m/s, is given by u(r) 5 4(1

xxMikexx [17]

The question is not clear and the complete clear question is;

The velocity profile in fully developed laminar flow In a circular pipe of inner radius R = 2 cm, in m/s, is given By u(r) = 4(1 - r²/R²). Determine the average and maximum Velocities in the pipe and the volume flow rate.

Answer:

A) V_max = 4 m/s

B) V_avg = 2 m/s

C) Flow rate = 0.00251 m³/s

Explanation:

A) We are given that;

u(r) = 4(1 - (r²/R²))

To obtain the maximum velocity, let's apply the maximum condition for a single-variable continual real valued problem to obtain;

(d/dr)(u(r)) = 0

Thus,

(d/dr)•4(1 - (r²/R²)) = 0

4(d/dr)(1 - (r²/R²)) = 0