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adell [148]
4 years ago
15

Tracy makes a list of energy transformations that occur as an engine runs to power a car.

Physics
2 answers:
kari74 [83]4 years ago
8 0

Answer: The correct answer is "Chemical energy transforms into gravitational potential energy".

Explanation:

In the given problem, an engine runs to power a car. The internal combustion engine in the car is gasoline which converts chemical energy into the thermal energy. Then, this thermal energy gets converted into kinetic energy by causing to power a car.

The chemical energy is obtained from the fuel which is in an engine of the car converts into thermal energy.

The thermal energy is generated in an engine of the car converts into the electrical energy so that the car can be started.

There is no use of gravitational potential energy in a car as it is due to the height above the ground.

Therefore, the correct option is (3).

makvit [3.9K]4 years ago
3 0

3. Chemical energy transforms into gravitational potential energy.

Explanation:

First of all, let's check the definition for each type of energy:

- Chemical energy is the energy stored in the chemical bonds inside compounds and substances

- Thermal energy is the energy due to the random motion of atoms/molecules (heat)

- Electrical energy is the energy related to the motion of electrical charges

- Gravitational potential energy is the energy of an object which is placed at some height above the ground

- Kinetic energy is the energy of an object in motion

Given this definition, we can check each energy transformation to see which one are really involved in the engine used to power the car:

1. Chemical energy transforms into thermal energy. --> YES. This one is present: in fact, the chemical energy contained in the fuel is converted inside the engine into heat (thermal energy)

2. Thermal energy transforms into electrical energy. --> YES. The heat (thermal energy) used in the engine is converted into electrical energy used to turn on the car.

3. Chemical energy transforms into gravitational potential energy. --> NO. There is no gravitational potential energy involved in this example, since the car runs on the ground.

4. Thermal energy transforms into kinetic energy. --> YES. The heat (thermal energy) used in the engine is converted into energy of motion of the car.

Therefore, Tracy should remove option 3) from her list.

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Una barra de plata de 335.2 g con una temperatura de 100 ºC se introduce un calorímetro de aluminio de 60 g de masa que contiene
sdas [7]

Respuesta:

0,0560 cal / gºC.

Explicación:

Cantidad de calor; (Q)

Q = mcΔt; Δt = t2 - t1

m = masa, c = capacidad calorífica específica; Δt = cambio de temperatura

c de agua = 1 cal / gºC

c de aluminio = 0,22 cal / gºC

QTotal = Q de agua + Q de aluminio

Q de agua = 450 * 1 * (26 - 23) = 1350 cal

Q de aluminio = 60 * 0.22 * (26 - 23) = 39.6 cal

QTotal = 1350 + 39,6 = 1389,6 cal

Calor perdido = calor ganado

QTotal = calor perdido

- 1389,6 = 335,2 * c * (26 - 100)

-1389,6 = −24804,8 * c

c = 1389,6 / 24804,8

c = 0,056021 cal / gºC.

Capacidad calorífica específica de la plata = 0,0560 cal / gºC.

8 0
3 years ago
Explain whether a tennis ball dropped from a high distance experiences an elastic collision or inelastic collision
hodyreva [135]
I need help on that too poop head
4 0
3 years ago
What angle will give you the maximum range (horizontal displacementon a projectile? ( 3 pts)
natulia [17]

Answer:

45 degrees

Explanation:

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

8 0
2 years ago
A hippo drives 42 km due East. He then turns and drives 28 km at 25° East of South. He turns again and drives 32 km at 40° North
ch4aika [34]

Answer:

a) Please, see the attched figure

b) Total displacement R = (78.3 km; -4.8 km)

c) R = (78.4 km * cos (-3.5°); 78.4 km * sin (-3.5°))

d) The hippo is 78.4 km from his starting point.

The total distance traveled is 102 km

Explanation:

a)Please, see the attached figure.

b) The vector A can be expressed as:

A = (magnitude * cos α; magnitude * sin α)

Where

magnitude = 42 km

α= 0

Then,

A = (42 km ; 0) or 42 km i

In the same way, we can proceed with the other vectors:

B = ( Bx ; By)

where

(apply trigonometry of right triangles: sen α = opposite / hypotenuse and

cos α = adjacent / hypotenuse. See the figure to determine which component of vector B is the opposite and adjacent side to α)

Bx = 28 km * sin 25 = 11.8 km

By = 28 km * cos 25 = -25.4 km (it has to be negative since it is directed towards the negative vertical region according to our reference system)

B = (11.8 km; -25.4 km) or 11.8 km i - 25.4 km j

C = (Cx; Cy)

where

Cx = 32 km * cos 40° = 24.5 km

Cy = 32 km * sin 40 = 20.6 km

C = (24.5 km; 20.6 km)

Then:

R = A+B+C = (42 km + 11.8 km + 24.5 km; 0 - 25.4 km + 20.6 km)

= (78.3 km; -4.8 km) or 78.3 km i -4.8 km j

c) R = (78.3 km; -4.8 km)

The magnitude of R is:

magnitude = \sqrt{(78.3)^{2 }+ (-4.8)^{2}}= 78.4 km

Using trigonometry, we can calculate the angle:

Knowing that

tan α = opposite / adjacent

and that

opposite = Ry = -4.8 km

adjacent = Rx = 78.3 km

Then:

tan α = -4.8 km / 78.4 km

α = -3.5°

We can now write the vector R in magnitude and direction form:

R = (78.4 km * cos (-3.5°); 78.4 km * sin (-3.5°))

d) The displacement of the hipo relative to the starting point is the magnitude of vector R calculated in c):

magnitude R = 78. 4 km

The total distance traveled is the sum of the magnitudes of each vector:

Total distance = 42 km + 28 km + 32 km = 102 km  

3 0
3 years ago
HELP!!!!! Please hurry up
Degger [83]

it's def. TRUE. i got the same question and i got it right

6 0
4 years ago
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