Answer:
vavg = 53.7 km/h
Explanation:
In order to find the magnitude of the bus'average velocity, we need just to apply the definition of average velocity, as follows:

where xf - xo = total displacement = 1250 Km
If we choose t₀ = 0, ⇒ t = 23h 16'= 23h + 0.27 h = 23.27 h
⇒ 
Answer:
W = 7056 J
Explanation:
Given that,
Mass of a load, m = 60 kg
Distance moved, d = 12 m
We need to find the amount of work. The work done by an object is given by :
W = Fd
So,
W = mg×d
W = 60 kg × 9.8 m/s²×12 m
W = 7056 J
So, the amount of work done is 7056 J.
Answer:
The answer is 3.33m
Explanation:
The acceleration "a" is constant.
Acceleration is the variation of velocity over time,
.
solving the last equation
,
where
because the airplane starts from rest.
Once again, velocity is the variation of distance over time.

then

where
if we consider the end of the runway as the initial point (this step is for simplicity but you can let it expressed, it's going to cancel anyway).
If
at
, then

and the final expression for the distance is
.
If t = 2s, x = 4.44 m. Which means thad the additional distance is

Mass and energy are equivalent. I'm doing the same test right now.