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-Dominant- [34]
3 years ago
8

A student has a sample of an insoluble solid and a liquid. The task is to separate the mixture into its pure components. What qu

estion is best asked in the design of the experiment to determine how to separate the components?
A) Is the solid/liquid mixture toxic in its combined form?

B) Is the solid large enough to be caught by the pores of a filter?

C) Is the melting temperature of the solid lower than that of the liquid?

D) Can the solid be crushed into smaller particles to allow for distillation?
Physics
1 answer:
neonofarm [45]3 years ago
6 0

Answer:

<em><u></u></em>

  • <em><u>B) Is the solid large enough to be caught by the pores of a filter? </u></em>

Explanation:

An <em>insoluble solid</em> and a <em>liquid</em> form an heterogeneous mixture, meaning the liquid and the solid could be <em>separated</em> by physical media.

If the size of the solid particles are large enough it could be separated from the liquid by filtration.

Since, the task is to separate the mixture into its pure components, the best and first step is to determine whether the solid particles have the size that permit to retain them in the available fliter, which is described by<em> </em>the option <em>B): is the solid large enough to be caught by the pores of a filter? </em>

As for the other options:

<em>A) Is the solid/liquid mixture toxic in its combined form?</em>

  • a mixture is not more toxic than its pure components, because they are a physical combination and not a chemical one.

<em>C) Is the melting temperature of the solid lower than that of the liquid?</em>

  • you do not want to melt the solid, because that would make the separation more difficult.

<em>D) Can the solid be crushed into smaller particles to allow for distillation? </em>

  • crushing the solid will not make it soluble and will not change the boiling point of the solution, thus this is not a step to separate the mixture into its components.
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A pendulum has 294 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
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Newton's law of conservation states that energy of an isolated system remains a constant. It can neither be created nor destroyed but can be transformed from one form to the other.


Implying the above law of conservation of energy in the case of pendulum we can conclude that at the bottom of the swing the entire potential energy gets converted to kinetic energy. Also the potential energy is zero at this point.


Mathematically also potential energy is represented as


Potential energy= mgh


Where m is the mass of the pendulum.


g is the acceleration due to gravity


h is the height from the bottom z the ground.


At the bottom of the swing,the height is zero, hence the potential energy is also zero.


The kinetic energy is represented mathematically as


Kinetic energy= 1/2 mv^2


Where m is the mass of the pendulum


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At the bottom the pendulum has the maximum velocity. Hence the kinetic energy is maximum at the bottom.


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What is the force exerted on a charge of 2. 5 µC moving perpendicular through a magnetic field of 3. 0 × 102 T with a velocity o
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The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.

<h3>What is the force exerted on the charge?</h3>

Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.

when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.

Mathematically the force exerted on the charge will be

F=qvBsinα

F= force acting on the charge

v = velocity of charge

q = charge

F=qvBsinα

F=2.5×10⁻⁶×5.0×10³×3.0×10²

F=37.5 N

Hence The force acting on the charge will be 3.75 N.

To learn more about the force acting on charge refer to ;

brainly.com/question/451411

F = q V B sinα

Where F is the force applied to a moving charge.

V = charge velocity

q stands for charge.

α = angle between V and B directions

As a result, the moving charge is subjected to a force of 3.75 Newton.

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