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GalinKa [24]
3 years ago
6

An 80-cm uniform 10-kg bar is resting on two scales, one at either end. A smaller 4-kg mass (m) is placed at a distance of d = 2

0 cm from the left end. Because the mass is closer to the left scale, it reads a higher weight than the right scale. What is the difference between the weights read by the two scales (left scale minus right scale)?
Physics
1 answer:
Varvara68 [4.7K]3 years ago
7 0

Answer

given,

length of bar = 80 cm

mass of the bar = 10 kg

smaller mass = 4 kg

distance = 20 cm

s_1 + s_2 = 10 + 4

s_1 + s_2 = 14\ kg

taking moment about B

s_1 \times 0.8 - 10 \times 0.4 - 4 \times 0.6 = 0

s_1 \times 0.8 = 6.4

s_1 = 8\ N

s_2 = 14 - s_1

s_2 = 14 - 8

s_2 = 6 N

difference between two scale = 8 - 6

                                                  = 2 N

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Explanation:

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m (1.8 + 1.8 + 1.8 +4.5) = 5 m v

v = \dfrac{9.9}{5}

v = 1.98\ m/s

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