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3 years ago

At a fabrication plant, a hot metal forging has a mass of 75 kg and a specific heat

Physics

1 answer:

Lesechka [4]3 years ago

3 0

Answer:

940°C

Explanation:

Heat lost by the forging = heat gained by the oil

-mCΔT = mCΔT

-(75 kg) (430 J/kg/°C) (47°C − T) = (710 kg) (2700 J/kg/°C) (47°C − 32°C)

-32250 (47°C − T) = 1917000 (15°C)

47°C − T = -892°C

T = 939°C

Rounded to two significant figures, the initial temperature is 940°C.

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O ônibus espacial,preso sobre o avião está em movimento ou repouso?

marissa [1.9K]

Movimento es correcto

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3 years ago

A solenoid with 35 turns per centimeter carries a current I. An electron moves within the solenoid in a circle that has a radius

castortr0y [4]

Answer:

The current of the solenoid is 0.0129 A.

Explanation:

The movement of the electron within the solenoid in a circle is produced by equaling the magnetic force and the centripetal force, as follows:

$F_{B} = F_{c}$

$e*v \mu_{0}*n*I = \frac{m*v^{2}}{r}$

$I = \frac{m*v}{e* \mu_{0}*n*r}$

Where:

I: is the current

m: is the electron's mass = 9.1x10⁺³¹ kg

v: is the electron's speed = 3.0x10⁵ m/s

μ₀: is the permeability magnetic = 4πx10⁻⁷ T.m/A

n: is the number of turns per unit length = 35/cm

r: is the radius of the circle = 3.0 cm

e: is the electron's charge = 1.6x10⁻¹⁹ C

$I = \frac{m*v}{e*\mu_{0}*n*r} = \frac{9.1 \cdot 10^{-31} kg*3.0 \cdot 10^{5} m/s}{1.6 \cdot 10^{-19} C*4\pi \cdot 10^{-7} T.m/A*3500/m*0.03 m} = 0.0129 A$

Therefore, the current of the solenoid is 0.0129 A.

I hope it helps you!

3 0

3 years ago

Betelgeuse is how many times larger than the sun

Aleksandr-060686 [28]

Betelgeuse is one of the largest known stars and is probably at least the size of the orbits of Mars or Jupiter around the sun. That's a diameter about 700 times the size of the Sun or 600 million miles. For a star it has a rather low surface temperature (6000 F compared to the Sun's 10,000 F).

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3 years ago

A small block with a mass of 0.0600 kg is attached to a cord passing through a hole in a frictionless, horizontal surface (Figur

pogonyaev

Answer with Explanation:

We are given that mass of block=0.0600 kg

Initial speed of block=0.63 m/s

Distance of block from the hole when the block is revolved=0.47 m

Final speed=3.29 m/s

Distance of block from the hole when the block is revolved= $9\times 10^{-2}m$

a.We have to find the tension in the cord in the original situation when the block has speed = $v_0=0.63 m/s$

$T=\frac{mv^2}{r}$

Because tension is equal to centripetal force

Substitute the values

$T=\frac{0.06\times (0.63)^2}{0.47}=0.05 N$

b. $v=3.29 m/s$

$T=\frac{mv^2}{r}=\frac{0.06\times (3.29)^2}{0.09}=7.2 N$

c.Work don=Final K.E-Initial K.E

$W=\frac{1}{2}m(v^2-v^2_0)$

$W=\frac{1}{2}(0.06)((3.29)^2-(0.63)^2)$

$W=0.31 J$

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3 years ago

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