Answer is: 9,7 L is needed to store helium gas.
n(He) = 0,80 mol.
p(He) = 204,6 kPa.
T = 300 K.
R = 8,314 J/K·mol; universal gas constant.
Use ideal law eqaution: p·V = n·R·T.
V = n·R·T / p.
V(He) = 0,80 mol · 8,314 J/K·mol · 300 K ÷ 204,6 kPa.
V(He) = 9,75 L.
Answer:This is what's known as a metal displacement reaction: the lead substitutes for the copper and ends up precipitating out of solution as insoluble lead (II) sulfate. ... The weight of copper deposited was 15.86gm.
Explanation:
Answer:
Attached is the solution to the question
Explanation:
It will be easier to answer if you show the choices.
