From 1st EQ. of uniform motion
1)20.9-3.44/6=t=2.91 sec
2)28= 0+4.22a
a=6.66m/sec^2
3) Instantaneous acceleration
Answer:
D
Explanation:
I think the answer is D, because of hallucinations
Answer:
2763.53411 m/s
Explanation:
M = Mass of Earth = 5.972 × 10²⁴ kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Radius of Earth = 6371000 m
= Launch velocity
= Final velocity = 500 m/s
h = Altitude = 400 km
m = Mass of satellite
As the energy of the system is conserved we have
The launch speed of the satellite should be 2763.53411 m/s
Answer:
I’d they are curious they get more opportunities to find or explore new things.
Explanation: