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mr Goodwill [35]
3 years ago
11

a 1.00 kg mass is placed at the free end of a compressed spring. The force constant of the spring is 115 N/m. The spring has bee

n compressed 0.200 m from its neutral position. it is now released. neglecting the mass of the spring and assuming that the mass is sliding on a frictionless surface, how fast will the mass move as it passes the neutral position of the spring?
Physics
1 answer:
frosja888 [35]3 years ago
8 0

Here 1 kg mass is hold against compressed spring

when it is released and reached to natural position it will start moving with certain speed

As per energy concept we will now say that potential energy stored in the spring will convert into kinetic energy of the block

so here we will say

U_{spring} = KE_{block}

\frac{1}{2}kx^2 = \frac{1}{2}mv^2

115(0.20)^2 = 1.00(v^2}

v = 2.145 m/s

so block will released with speed 2.145 m/s

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Why do organs have different types of tissues?<br><br><br> PLZ HELP
Setler [38]

Explanation:

its hard to explain its very complex but its so they can function properly

6 0
3 years ago
A mad scientist wants to collect massive amounts of charge on basketball sized aluminum balls. The scientist wants to place 6 C
vitfil [10]

The distance between two basket ball sized aluminium balls is 9714 m.

Explanation:

Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force .

Coulomb's law formula => F = (k * Qb1 * Qb2)/r²

Given data :-

charge on ball 1 Qb1 = 6C

charge on ball 2 Qb2 = 14C

Force exerted F = 8000 N

k =  8.988 x 10^9 Nm²C−²(coulomb's constant).

substituting given values in the coulomb's formula

8000 = (( 8.988 x 10^9)*6*14)/r²

shifting r and 8000 to other sides

r² = (756 * 10^9)/8000

r = 9714 m.

Therefore the distance between two balls is r = 9714 m.

4 0
3 years ago
A 70 ft rope hangs from a helicopter above this room. The rope has a mass per unit length of 2 lb/ft. In order to be rescued fro
Mrac [35]

Answer:

The work done to get you safely away from the test is  2.47 X 10⁴ J.

Explanation:

Given;

length of the rope, L = 70 ft

mass per unit length of the rope, μ = 2 lb/ft

your mass, W = 120 lbs

mass of the 70 ft rope  = 2 lb/ft x 70 ft

                                         = 140 lbs.

Total mass to be pulled to the helicopter, M = 120 lbs  + 140 lbs  

                                                                       = 260 lbs

The work done is calculated from work-energy theorem as follows;

W = Mgh

where;

g is acceleration due gravity = 32.17 ft/s²

h is height the total mass is raised = length of the rope = 70 ft

W = 260 Lb x 32.17 ft/s²  x 70 ft

W = 585494 lb.ft²/s²

1 lb.ft²/s² = 0.0421 J

W = 585494 lb.ft²/s²  = 2.47 X 10⁴ J.

Therefore, the work done to get you safely away from the test is  2.47 X 10⁴ J.

4 0
2 years ago
7) T F If two forces of equal magnitude act on an object that is hinged at a pivot, the force acting farther from the pivot must
saul85 [17]

Answer:

False

Explanation:

The torque exerted by a force is given by:

\tau=Fd sin \theta

where

F is the magnitude of the force

d is the distance between the point of application of the force and the pivot

\theta is the angle between the directions of F and d

We see that the magnitude of the torque depends on 3 factors. In this problem, we have 2 forces of equal magnitude (so, equal F). Moreover, one of the forces (let's call it force 1) acts farther from the pivot than force 2, so we have

d_1 > d_2

However, this does not mean that force 1 produces a greater torque. In fact, it also depends on the angle at which the force is applied. For instance, if the first force is applied parallel to d, then we have

\theta_1 =0\\sin \theta=0

and the torque produced by this force would be zero.

So, the statement is false.

4 0
3 years ago
Consider the electric force between a pair of charged particles a certain distance apart. By Coulomb's Law: If instead, the char
Westkost [7]

Answer:

the answer is d

Explanation:

from F=Q1Q2

r².

then wen both charges are doubled

F=2Q1 ×2Q2

r²

F=4Q1Q2

r²

then 4 has to be the factor multiplied by the other part of the equation for it to balance

4F=4Q1Q2

r²

so theoretically the 4 on the LHS can cancel the 4 on the RHS

5 0
3 years ago
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