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mr Goodwill [35]
2 years ago
11

a 1.00 kg mass is placed at the free end of a compressed spring. The force constant of the spring is 115 N/m. The spring has bee

n compressed 0.200 m from its neutral position. it is now released. neglecting the mass of the spring and assuming that the mass is sliding on a frictionless surface, how fast will the mass move as it passes the neutral position of the spring?
Physics
1 answer:
frosja888 [35]2 years ago
8 0

Here 1 kg mass is hold against compressed spring

when it is released and reached to natural position it will start moving with certain speed

As per energy concept we will now say that potential energy stored in the spring will convert into kinetic energy of the block

so here we will say

U_{spring} = KE_{block}

\frac{1}{2}kx^2 = \frac{1}{2}mv^2

115(0.20)^2 = 1.00(v^2}

v = 2.145 m/s

so block will released with speed 2.145 m/s

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A student of weight 659 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude
Misha Larkins [42]

Answer:

a) The student feel light

b) Nbottom = 758 N

c) N'top= 236 N

d) N'bottom= 1055 N

Explanation:

a) W= 659N , Ntop= 560N

W > Ntop ---> Student feel less weight

b)   Top:

∑F= W - Ntop = m.v²/R

m.v²/R = 659N - 560 N = 99 N

Bottom:

∑F= Nbottom- W = m.v²/R

Nbottom= W + m.v²/R = 659N + 99 N = 758N

c) W= 659 N , Ntop= 560 N , v'=2.v

N'top= ?

∑F= W - N'top = m.v'²/R

N'top= W - 4.m.v²/R

N'top = 659 N - 4. 99 N = 263 N

d)   N'bottom = ?

∑Fbottom= N'bottom- W = m.v'²/R

N'bottom = W + 4.m.v²/R = 659 N + 4. 99 N = 1055 N

4 0
2 years ago
A billiard ball travels 23 cm in the positive direction , hits the cushion and rebounds in the negative direction , and Finally
wel

Explanation :

Displacement refers to the distance between the final and the initial position. Hence the displacement of the ball will be the difference between the initial and the final displacement.

Let the initial position be 0.

Final position = 8 cm

So the difference between initial position and final position = 0 – 8 = - 8 cm.

So the billiard ball comes to rest 8.0 cm behind its orbital position.

4 0
3 years ago
Which of the following is always true about the particles that make up matter? A. They can only be found in solid substances. B.
Neko [114]
B.They are too small to be seen with only our eyes
4 0
3 years ago
Read 2 more answers
Par 1/2
BaLLatris [955]

part 1

mass = ρ x V

mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg

PE (potential energy)= mgh

PE = 6608.2 kg x 9.81 x 403

PE = 2.61 x 10⁷ J

part 2

megaton of TNT (Mt) =4.2 x 10¹⁵ J

convert PE to Mt:

2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt

4 0
2 years ago
How is the surface area of an average person is 2m^2 in the chapter pressure
11Alexandr11 [23.1K]

Answer:

We have to show surface area =2m^2,with few conditions that is by considering Force =200000\ N and Pressure =100000\ Pa to be respectively.

Explanation:

The atmospheric pressure is =10^{5}\ Pa on Earth's surface.

The magnitude of the force exerted on a person by the atmosphere is =2\times 10^{5}\N (or)\ 200kN\ (or)\ 20\ ton.

Now to calculate surface area we can find it from pressure=\frac{force}{area} and re-arranging it to.

area=\frac{force}{pressure}

So plugging the values,

Surface area =\frac{20000}{10000}=2\ m^{2}

Hence from the above calculations we can say that surface area is 2m^2.

So the surface area of an average person can be said to have 2m^2, using the concept of pressure and force.

3 0
3 years ago
Read 2 more answers
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