Explanation:
its hard to explain its very complex but its so they can function properly
The distance between two basket ball sized aluminium balls is 9714 m.
Explanation:
Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force .
Coulomb's law formula => F = (k * Qb1 * Qb2)/r²
Given data :-
charge on ball 1 Qb1 = 6C
charge on ball 2 Qb2 = 14C
Force exerted F = 8000 N
k = 8.988 x 10^9 Nm²C−²(coulomb's constant).
substituting given values in the coulomb's formula
8000 = (( 8.988 x 10^9)*6*14)/r²
shifting r and 8000 to other sides
r² = (756 * 10^9)/8000
r = 9714 m.
Therefore the distance between two balls is r = 9714 m.
Answer:
The work done to get you safely away from the test is 2.47 X 10⁴ J.
Explanation:
Given;
length of the rope, L = 70 ft
mass per unit length of the rope, μ = 2 lb/ft
your mass, W = 120 lbs
mass of the 70 ft rope = 2 lb/ft x 70 ft
= 140 lbs.
Total mass to be pulled to the helicopter, M = 120 lbs + 140 lbs
= 260 lbs
The work done is calculated from work-energy theorem as follows;
W = Mgh
where;
g is acceleration due gravity = 32.17 ft/s²
h is height the total mass is raised = length of the rope = 70 ft
W = 260 Lb x 32.17 ft/s² x 70 ft
W = 585494 lb.ft²/s²
1 lb.ft²/s² = 0.0421 J
W = 585494 lb.ft²/s² = 2.47 X 10⁴ J.
Therefore, the work done to get you safely away from the test is 2.47 X 10⁴ J.
Answer:
False
Explanation:
The torque exerted by a force is given by:

where
F is the magnitude of the force
d is the distance between the point of application of the force and the pivot
is the angle between the directions of F and d
We see that the magnitude of the torque depends on 3 factors. In this problem, we have 2 forces of equal magnitude (so, equal F). Moreover, one of the forces (let's call it force 1) acts farther from the pivot than force 2, so we have

However, this does not mean that force 1 produces a greater torque. In fact, it also depends on the angle at which the force is applied. For instance, if the first force is applied parallel to d, then we have

and the torque produced by this force would be zero.
So, the statement is false.
Answer:
the answer is d
Explanation:
from F=Q1Q2
r².
then wen both charges are doubled
F=2Q1 ×2Q2
r²
F=4Q1Q2
r²
then 4 has to be the factor multiplied by the other part of the equation for it to balance
4F=4Q1Q2
r²
so theoretically the 4 on the LHS can cancel the 4 on the RHS