Answer:
overspeeding,
see if we calculate the speed or average speed,
it would be 159/2 which would be 79.5mph,
so as posted speed was 65mph, but the average speed was 79.5mph(Meaning most of the time she would have been above 65 mph), So,
She would have been charged with overspeeding
HOPE IT HELPS
BYE!
Answer:
i can not be cas thae are the same
Step-by-step explanation:
Answer:
perpendicular line through a point on a line
Step-by-step explanation:
The circle centered at C seems intended to produce point D at the same distance as point B. That is, C is the midpoint of BD.
The circles centered at B and D with radius greater than BC seems intended to produce intersection points G and H. (It appears accidental that those points are also on circle C. As a rule, that would be difficult to do in one pass.)
So. points G and H are both equidistant from points B and D. A line between them will intersect point C at right angles to AB.
Segment GH is perpendicular to AB through point C (on AB).
Given:


To find:
The value of
.
Solution:
We have,


Using properties of log, we get
![\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D%5Clog_am-%5Clog_an%5Cright%5D)
![[\log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Clog%20x%5En%3Dn%5Clog%20x%5D)
Substitute
and
.



Therefore, the value of
is
.