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3 years ago

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The spaceship Intergalactic landed on the surface of the uninhabited Pink Planet, which orbits a rather average star in the dist

ant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.44 m. She sets the pendulum swinging, and her collaborators carefully count 1.10×102 complete cycles of oscillation during 2.00×102 s. What is the result

1 answer:

max2010maxim [7]3 years ago

3 0

Answer:

<em>18808.7 m/s^2</em>

Explanation:

Given

Length of the pendulum L = 1.44 m

Number of complete cycles of oscillation n = 1.10 x 10^2

total time of oscillation t = 2.00 x 10^2 s

The period of the T = n/t

T = (1.10 x 10^2)/(2.00 x 10^2) = 0.55 ^-s

The period of a pendulum is gotten as

T = $2\pi \sqrt{\frac{L}{g} }$

where g is the acceleration due to gravity

substituting values, we have

0.55 = $2\pi \sqrt{\frac{1.44}{g} }$

0.0875 = $\sqrt{\frac{1.44}{g} }$

squaring both sides of the equation, we have

7.656 x 10^-3 = 144/g

g = 144/(7.656 x 10^-3) = <em>18808.7 m/s^2</em>

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Answer:0.061

Explanation:

Given

$T_C=300 k$

Temperature of soup $T_H=340 K$

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Fraction of the total heat that is lost by the soup can be turned is given by

$=\frac{W}{Q}$

$=\frac{c_v\left [ \left ( T_C-T_H\right )-T_C\left ( \ln \frac{T_C}{T_H}\right )\right ]}{c_v(T_C-T_H)}$

$=\frac{T_C-T_H-T_C\ln (\frac{T_C}{T_H})}{T_C-T_H}$

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To calculate the acceleration we must know the electric field. The electric field and the potential are related by:

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