Answer:
Explanation:
2Al(s) + 3 2 O2(g) → Al2O3(s) And given the stoichiometry ...and EXCESS dioxygen gas...we would get 6.25⋅ mol of alumina. the which represents a mass... ...6.25 ⋅ mol ×101.96 ⋅ g ⋅ mol−1 molar mass of alumina ≡ 637.25 ⋅ g.
H2 + O -> H2O
I'm pretty sure that's the answer, just tell me if I'm wrong.
<span>This family of elements is headed by boron. In this case, atomic size increases as one goes down the periodic table, as there are more electrons in each successive element needed to fill the outer shells. As such, thallium, at the lowest level of the group 3a column, will have the largest atomic size.</span>
I believe transition metals are coinage metals. The answer should be A.
