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FromTheMoon [43]
4 years ago
11

If a particular ore contains 55.4 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp

horus?
Chemistry
1 answer:
gizmo_the_mogwai [7]4 years ago
8 0
 The ore contains 55.4% calcium phosphate (related to the mineral apatite) so the amount of Ca3(PO4)2 is 55.4%x=1000g so x=1000/0.554= 1.805kg. Now for the % of P in this amount of calcium phosphate, use all the masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95  (NB oxygen is 16 mass x 4 =64) so the total mass is 310.2 and we have 61.95 of P (Pmass x 2) so 61.95/3102.= 0.19 or 19% P. So of the 1.805 x 0.19= 0.34kg of phosphorus.
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gulaghasi [49]

Answer:

because it has lighter molecules.

4 0
3 years ago
Which substance is the oxidizing agent in this reaction? fe2o3+3co→2fe+3co2 express your answer as a chemical formula?
erma4kov [3.2K]
Equation is as follow,

                            Fe₂O₃  +  3 CO     →     2 Fe  +  3 CO₂

Oxidation:

                                        3 CO     →     3 CO₂

Oxidation state of C in CO is +2, and that in CO₂ is +4. So, carbon has lost 2 electrons per mole and 6 electrons per 3 moles hence,

                                 3 CO     →     3 CO₂  +  6 e⁻

Reduction:

                                    Fe₂O₃     →     2 Fe

Oxidation state of Fe in Fe₂O₃ is +3 per atom, and that in Fe is 0. So, Iron has gained 3 electrons per atom and 6 electrons per 2 atoms hence,

                                    Fe₂O₃  +  6e⁻     →     2 Fe

Result:
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4 0
3 years ago
As
Mars2501 [29]

Explanation:

  1. area of rectangle=l×b
  • 15=5×b
  • b=3cm

2.area of rectangle=l×b

  • 28=l×4
  • l=7cm

3. perimeter of square=4×L

  • 24=4×L
  • L=6cm

4. perimeter of rectangle=2(L+b)

  • 14=2(4+b)
  • 14=8+2b
  • 2b=6
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hope it helps.

4 0
3 years ago
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It was observed that a normal pressure the gas allowed the current to pass through the cathode tube
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False is the correct answer
3 0
3 years ago
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