Answer:
0.166 m or 16.6 cm
Explanation:
From the question,
v = ωr......................... Equation 1
Where v = tangential speed of the string, ω = Angular speed of the string, r = Length of the rotating string.
make r the subject of the equation
r = v/ω....................... Equation 2
Given: v = 50 m/s, ω = 48 rev/s = 48(2π) rad/s = 48(2×3.14) rad/s = 301.44 rad/s.
Substitute into equation 2
r = 50/301.44
r = 0.166 m or 16.6 cm
Hence the length of the rotating string = 0.166 m or 16.6 cm
