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Olegator [25]
3 years ago
9

A string trimmer is a tool for cutting grass and weeds; it utilizes a length of nylon "string" that rotates about an axis perpen

dicular to one end of the string. The string rotates at an angular speed of 48 rev/s, and its tip has a tangential speed of 50 m/s. What is the length of the rotating string?
Physics
1 answer:
Morgarella [4.7K]3 years ago
4 0

Answer:

0.166 m or 16.6 cm

Explanation:

From the question,

v = ωr......................... Equation 1

Where v = tangential speed of the string, ω = Angular speed of the string, r = Length of the rotating string.

make r the subject of the equation

r = v/ω....................... Equation 2

Given: v = 50 m/s, ω = 48 rev/s = 48(2π) rad/s = 48(2×3.14) rad/s = 301.44 rad/s.

Substitute into equation 2

r = 50/301.44

r = 0.166 m or 16.6 cm

Hence the length of the rotating string = 0.166 m or 16.6 cm

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A lunch pail is accidentally kicked off a steel beam on a building under construction. Suppose the initial horizontal speed is 1
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1) 26.6 m

Along the horizontal direction, the lunch pail is moving with a uniform motion (constant speed), since there are no forces acting in this direction.

Therefore, the distance travelled horizontally after a time t is given by:

d=v_x t

where we know

v_x = 1.50 m/s is the horizontal velocity

d = 3.50 m is the distance covered horizontally

Solving for t, we find the total time of the motion:

t=\frac{d}{v_x}=\frac{3.50}{1.50}=2.33 s

Now we know that the pail takes 2.33 s to fall to the ground. We can now consider the vertical motion of the pail, which is a free fall motion, so the vertical displacement is given by the equation

s=ut+\frac{1}{2}at^2

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u = 0 is the initial vertical velocity

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Substutting t = 2.33 s, we find how fat the pail has fallen:

s=\frac{1}{2}(9.8)(2.33)^2=26.6 m

2) 10.7 m

In this case, we know instead the vertical displacement:

s=2.50\cdot 10^2 m = 250 m

Therefore, we can use the same equation again

s=ut+\frac{1}{2}at^2

To find the total time of motion:

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(250)}{9.8}}=7.14 s

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So, the horizontal distance covered in this time is

d=v_x t = (1.50)(7.14)=10.7 m

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4 years ago
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