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quester [9]
3 years ago
6

What is a p-n junction? Show by the diagram.

Engineering
1 answer:
Natalija [7]3 years ago
5 0

Answer:

The p-n junction is a region formed when a p -type semiconductor material is joined to an n-type semiconductor material

Explanation:

The p type semiconductor has holes as its majority charge carriers making it positively charged while the n –types has an overall negative charge. At the junction the holes move towards the electron until such a time when there is a balance in charges from both materials, which leads to the formation of the depletion zone as shown in the attachment below

                           

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2 years ago
Discuss the differences between conduction and convective heat transfer.
FrozenT [24]

Answer:

Basically there are two principal differences between the convection and conduction heat transfer

Explanation:

The conduction heat transfer is referred to the transfer between two solids due a temperature difference, while for, the convective heat transfer is referred to the transfer between a fluid (liquid or gas) and a solid. Also, they used different coefficients for its calculation.

We can include on the explanation that conduction thermal transfer is due to temperature difference, while convection thermal transfer is due to density difference.

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2 years ago
Choose two consumer services careers and research online to determine what kinds of professional organizations exist for these p
Tom [10]

Answer:

Market Researcher

The Marketing Research Association (MRA) is a professional organization for market researchers. It provides information to its members on how to improve marketing research for businesses and individuals. The MRA gives its members important industry news and information through their website. Their code for marketing research standards also protects members from bad actors and improves the public perception of marketing research. The association also has a full time lobbyist representing the market research industry before government officials. The MRA has various membership categories as well. The membership fee differs for each category.  

Credit Analyst

A credit analyst is a person that reviews consumer or business financial profiles in order to give a loan or credit to them. When a business or individual applies for a credit card, loan, trade account, or another type of financial product whereby a company allows them the use of their money, a credit analyst’s job is to ensure that the consumer or business is willing and able to pay it back in the future. Credit analysts use tools such as credit reports, FICO scores, Dun & Bradstreet ratings, financial statement analyses, and personal references to perform their job. A credit analyst should have a bachelor’s degree with a major in business. Finance and economics majors are particularly suited to a credit analyst position. Certifications are not required, but some credit analysts pursue CPA or CFA (Certified Financial Analyst) designations.

Explanation:

5 0
3 years ago
(3) Calculate the heat flux through a sheet of brass 7.5 mm (0.30 in.) thick if the temperatures at the two faces are 150°Cand 5
bezimeni [28]

Answer:

a.) 1.453MW/m2,  b.)  2,477,933.33 BTU/hr  c.) 22,733.33 BTU/hr  d.) 1,238,966.67 BTU/hr

Explanation:

Heat flux is the rate at which thermal (heat) energy is transferred per unit surface area. It is measured in W/m2

Heat transfer(loss or gain) is unit of energy per unit time. It is measured in W or BTU/hr

1W = 3.41 BTU/hr

Given parameters:

thickness, t = 7.5mm = 7.5/1000 = 0.0075m

Temperatures 150 C = 150 + 273 = 423 K

                        50 C = 50 + 273 = 323 K

Temperature difference, T = 423 - 323 = 100 K

We are assuming steady heat flow;

a.) Heat flux, Q" = kT/t

K= thermal conductivity of the material

The thermal conductivity of brass, k = 109.0 W/m.K

Heat flux, Q" = \frac{109 * 100}{0.0075} = 1,453,333.33 W/m^{2} \\ Heat flux, Q" = 1.453MW/m^{2} \\

b.) Area of sheet, A = 0.5m2

Heat loss, Q = kAT/t

Heat loss, Q = \frac{109*0.5*100}{0.0075} = 726,666.667W

Heat loss, Q = 726,666.667 * 3.41 = 2,477,933.33 BTU/hr

c.) Material is now given as soda lime glass.

Thermal conductivity of soda lime glass, k is approximately 1W/m.K

Heat loss, Q=\frac{1*0.5*100}{0.0075} = 6,666.67W

Heat loss, Q = 6,666.67 * 3.41 = 22,733.33 BTU/hr

d.) Thickness, t is given as 15mm = 15/1000 = 0.015m

Heat loss, Q=\frac{109*0.5*100}{0.015} =363,333.33W

Heat loss, Q = 363,333.33 * 3.41 = 1,238,966.67 BTU/hr

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2 years ago
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creativ13 [48]

Answer: 5mW

Explanation:

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