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Juli2301 [7.4K]
3 years ago
8

The ratio of the weight of a substance to the weight of equal volume of water is known as a) Density b) specific gravity c) spec

ific weight d) bulk modulus
Engineering
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

c)specific weight

Explanation:

the ratio between the weight of a substance and the weight of the same volume of water is known as specific weight  this is a property that results in a dimensionless number since it consists of dividing the weight of a fluid by the weight of water in a same volume

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Which of the following best describes the role of engineers
Fantom [35]

Problem Solvers

Explanation:

Engineers find problems in the world, and then they find solutions for them.

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Who here likes to play project gotham racing?<br> will mark brainlyest
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Answer:

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Explanation:

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Consider a system whose temperature is 18°C. Express this temperature in R, K, and °F.
zvonat [6]

Answer:

In Rankine 524.07°R

In kelvin 291 K

In Fahrenheit 64.4°F  

Explanation:

We have given temperature 18°C

We have to convert this into Rankine R

From Celsius to Rankine we know that  T(R)=(T_{C}+273.15)\frac{9}{5}

We have to convert 18°C

So T(R)=(18+273.15)\frac{9}{5}=524.07^{\circ}R

Conversion from Celsius to kelvin

T(K)=(T_{C}+273)

We have to convert 18°C

T(K)=(18+273)=291K

Conversion of Celsius to Fahrenheit

T(F)=T_{C}\times \frac{9}{5}+32=64.4^{\circ}F

7 0
4 years ago
A diesel engine with CR= 20 has inlet at 520R, a maximum pressure of 920 psia and maximum temperature of 3200 R. With cold air p
Stella [2.4K]

Answer:

Cut-off ratio\dfrac{V_3}{V_2}=6.15

Cxpansion ratio\dfrac{V_4}{V_3}=3.25

The exhaust temperatureT_4=1997.5R

Explanation:

Compression ratio CR(r)=20

\dfrac{V_1}{V_2}=20

P_2=P_3=920 psia

T_1=520 R ,T_{max}=T_3,T_3=3200 R

We know that for air γ=1.4

If we assume that in diesel engine all process is adiabatic then

\dfrac{T_2}{T_1}=r^{\gamma -1}

\dfrac{T_2}{520}=20^{1.4 -1}

T_2=1723.28R

\dfrac{V_3}{V_2}=\dfrac{T_3}{T_2}

\dfrac{V_3}{V_2}=\dfrac{3200}{520}

So cut-off ratio\dfrac{V_3}{V_2}=6.15

\dfrac{V_1}{V_2}=\dfrac{V_4}{V_3}\times\dfrac{V_3}{V_2}

Now putting the values in above equation

\dfrac20=\dfrac{V_4}{V_3}\times 6.15

\dfrac{V_4}{V_3}=3.25

So expansion ratio\dfrac{V_4}{V_3}=3.25.

\dfrac{T_4}{T_3}=(expansion\ ratio)^{\gamma -1}

\dfrac{T_3}{T_4}=(3.25)^{1.4 -1}

T_4=1997.5R

So the exhaust temperatureT_4=1997.5R

3 0
4 years ago
A fluid flows along the x axis with a velocity given by V = (xt) i ˆ, where x is in feet and t in seconds. (a) Plot the speed fo
nataly862011 [7]

Answer

See explanation for step by step procedures towards getting answers

Explanation:

Given that;

A fluid flows along the x axis with a velocity given by V = (xt) i ˆ, where x is in feet and t in seconds. (a) Plot the speed for 0 ≤ x ≤ 10 ft and t = 3 s. (b) Plot the speed for x = 7 ft and 2 ≤ t ≤ 4 s. (c) Determine the local and convective acceleration. (d) Show that the acceleration of any fluid particle in the flow is zero. (e) Explain physically how the velocity of a particle in this unsteady flow remains constant throughout its motion.

See attachments for further explanations

7 0
3 years ago
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